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Novosadov [1.4K]
3 years ago
9

Re write the quadratic function in standard formy=6(x-3)^2+4

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

y= 6x^{2} - 36x + 58

Step-by-step explanation:

6 ( x^{2} - 6x +9) + 4

6x^{2} - 36x + 54 + 4

6x^{2} - 36x + 58

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\text{The scientific notation:}\\\\a\times10^n\\\\1\leq a


a.\\(5\times10^3)\times(3.5\times10^{-1})=(5\times3.5)\times(10^3\times10^{-1})\\\\=15.75\times10^{3+(-1)}=15.75\times10^2=1.575\times10\times10^2\\\\=1.575\times10^{1+2}=\boxed{1.575\times10^3}

b.\\(8\times10^2)\div(4\times10^3)=(8\div4)\times(10^2\div10^3)=2\times10^{2-3}\\\\=\boxed{2\times10^{-1}}

c.\\(6\times10^{-3})^2=6^2\times(10^{-3})^2=36\times10^{-3\cdot2}=36\times10^{-6}=3.6\times10\times10^{-6}\\\\=3.6\times10^{1+(-6)}=\boxed{3.6\times10^{-5}}

Used:\\\\a^n\times a^m=a^{n+m}\\\\a^n\div a^m=a^{n-m}\\\\(a^n)^m=a^{n\cdot m}

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3 years ago
What is the coefficient of q in the sum of (2/3q-3/4) and(-1/6q-r)?
Harlamova29_29 [7]

Answer:

The coefficient is \frac{1}{2}

Step-by-step explanation:

The given sum is

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We can choose to add only the coeffients of q or simplify the whole sum.

=\frac{2}{3}q -\frac{1}{6}q-\frac{3}{4})-r)

We collect the LCM for the q terms;

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This will give us;

=\frac{3}{6}q-\frac{3}{4})-r)

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=\frac{1}{2}q-r-\frac{3}{4}

The coefficient is \frac{1}{2}

6 0
3 years ago
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Step-by-step explanation:

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Answer:

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