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3 years ago

7

A certain television is advertised as a 36-inch TV (the diagonal length). If the width of the TV is 26 inches, how tall is the T

V? Round to the nearest tenth of an inch.

1 answer:

Aloiza [94]3 years ago

7 0

Answer:

the correct answer is 24.9

Step-by-step explanation:

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While waiting for a bus, Todd decided to play with consecutive numbers (whole numbers that increase in order without skipping, s

Lesechka [4]

Answer:

A: 8+9+10=27

9+10+11=30

10+11+12=13

B: 19+20+21

C: There isn't any.

Step-by-step explanation:

It just is lol.

4 0

4 years ago

Given: ⅓ (18x + 27) = 81 Prove: x = 12

sasho [114]

Answer:

Firstly, rewrite the equation:

⅓ (18 + 27) = 81

Substitute x for the given number of it's supposed equivalent.

In this case x = 12.

⅓ (18(12) + 27) = 81

Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.

(18 x 12) + 27 = 243

Now, solving using PEMDAS, multiply the total of what you got that was originally in the parenthesis by ⅓ .

⅓ (243) = 81

When you multiple these number they are equivalent to 81.

81 = 81

Since the equation given, when substituted x for 12, is equivalent to 81, this proves that substituting x for 12 makes this equation true.

4 0

3 years ago

Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly low, μ- 2σ , and the maximum val

allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

$n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\$

Using the binomial distribution: $\mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186$

In this the maximum value which is significantly low, $\mu-2\sigma$ , and the minimum value which is significantly high, $\mu+2\sigma$ , that is equal to:

$\mu-2\sigma = 22.32 - 2(4.1186) = 14.0828 \approx 14.08\\\\\mu+2\sigma = 22.32 + 2(4.1186) = 30.5572 \approx 30.56$

3 0

3 years ago

A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are

IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5 percent of these are defective.

This means that $p = 0.05$

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025$

0.0025 = 0.25% probability that both are defective

4 0

3 years ago

Write an expression to represent three minus the product of two and a number x

Rainbow [258]

<em>3 minus ___</em> ⇒ 3 - ___

<em>the product of 2 and a number x</em> ⇒ 2x

"3 minus the product of 2 and a number x" ⇒ 3 - 2x

_____

Each part of the description has a translation.

7 0

3 years ago