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Sidana [21]
4 years ago
6

A candy bar takes an average of 3.4 hours to move through an assembly line. If the standard deviation is 0.5 hours, what is the

probability that the candy bar will take between 3 and 4 hours to move through the line?. A:.2119 B:.2295 C:.6731 D:.3270 E:.8849. 2. the average noise level in a diner is 30 decibels with a standard deviation of 6 decibels. 99% of the time, the noise level is below what value?. A: 16.04 B: 30.00 C: 36.00 D: 43.96 E: 48.00.
Mathematics
1 answer:
stepladder [879]4 years ago
7 0
To answer the first problem, we determine first the equivalent z score and get the corresponding probability. The z score at 3 hours is (3-3.4)/0.5 = 0.8 while that of 4 hrs is <span>(4-3.4)/0.5 = 1.2. z score of 0.8 is equal to a probability of 0.2119 and that at 1.2 is 0.8849. The difference is 0.673. Hence answer is C. 
For problem 2, the z score at 99% is 2.33 hence, the equation becomes 2.33 = (x-30)/6 where x is the noise level threshold. Answer is D. 43.96 decibels.</span>
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Answer:

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Step-by-step explanation:

We can use the 2-point form of the equation of a line to write a function that gives Justin's salary as a function of his sales.

We start with (sales, salary) = (400, 500) and (700, 575)

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For sales of 2500, this will be ...

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Justin's salary after selling $2500 in merchandise is $1025.

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The second place runner had already completed 320 meters when the winner crossed the finish line

8 0
3 years ago
What is 36.993 to the nearest thousandth
finlep [7]

The next larger thousandth is 36.994 .
The next smaller thousandth is  36.992 .
Neither of those is any nearer to  36.993
than  36.993  already is.

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3 years ago
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Alenkasestr [34]

Answer:

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Step-by-step explanation:

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−3a+6=3

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−3a

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3 0
3 years ago
Read 2 more answers
Which expression is equivalent to
lutik1710 [3]

Answer:

\frac{\sqrt[4]{3x^2} }{2y}

Step-by-step explanation:

We can simplify the expression under the root first.

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Thus, we have:

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We know 4th root can be written as "to the power 1/4th". Then we can use the property  (ab)^{x}=a^x b^x

<em>So we have:</em>

<em>\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}</em>

<em />

<em>Option D is right.</em>

8 0
4 years ago
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