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suter [353]
3 years ago
13

A child's toy consists of a spherical object of mass 50 g attached to a spring. One end of the spring is fixed to the side of th

e baby's crib so that when the baby pulls on the toy and lets go, the object oscillates horizontally with a simple harmonic motion. The amplitude of the oscillation is 6 cm and the maximum velocity achieved by the toy is 3.2 m/s . What is the potential energy (U) of the toy when the spring is compressed 4.4 cm from its equilibrium position? *I found the KE, but need help on PE*
Physics
1 answer:
Artemon [7]3 years ago
6 0

Answer:

0.14 J

Explanation:

The maximum velocity is the amplitude times the angular frequency.

vmax = Aω

ω = vmax / A

ω = (3.2 m/s) / (0.06 m)

ω = 53.3 rad/s

For a spring-mass system:

ω = √(k / m)

ω² = k / m

k = ω²m

k = (53.3 rad/s)² (0.050 kg)

k = 142 N/m

The elastic potential energy is:

EE = ½ kx²

EE = ½ (142 N/m) (0.044 m)²

EE = 0.14 J

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