All categories

4 years ago

Label the following as either a homogenous mixture, heterogeneous mixture. element or compound.

1 answer:

3 0

1element
2compund
3heterogenous
4homogenous
5compound
6homogenous
7heterogenous
8heterogenous
9element
10element
Hope I helped! :D brainliest?

You might be interested in

For each of the scenarios, identify the order with respect to the reactant, A. A⟶products The half‑life of A increases as the in

nirvana33 [79]

Answer:

Answers are in the explanation.

Explanation:

The half‑life of A increases as the initial concentration of A decreases. order: 2. In the half-life of second-order reactions, the half-life is inversely proportional to initial concentration.
A three‑fold increase in the initial concentration of A leads to a nine‑fold increase in the initial rate. order: 2. The rate law of second-order is: rate = k[A]²
A three‑fold increase in the initial concentration of A leads to a 1.73‑fold increase in the initial rate. order: 1/2. The rate law for this reaction is: rate = k √[A]
The time required for [A] to decrease from [A]₀ to [A]₀/2 is equal to the time required for [A] to decrease from [A]₀/2 to [A]₀/4. order: 1. The concentration-time equation for first-order reaction is: ln[A] = ln[A]₀ - kt. That means the [A] decreasing logarithmically.
The rate of decrease of [A] is a constant. order: 0. The rate law is: rate = k -where k is a constant-

4 0

3 years ago

Which of the following best describes an electrical circuit?

Sergeeva-Olga [200]

Answer:

An electric circuit is best described as a loop.

the flow of electrons

Explanation:

3 0

4 years ago

How many moles of Cl2 are needed in order to produce 100.0 grams of FeCl3 given the following

dimulka [17.4K]

Answer:

0.92moles

Explanation:

Given reaction:

2Fe + 3Cl₂ → 2FeCl₃

Mass of FeCl₃ = 100g

Unknown:

Number of moles of Cl₂ needed = ?

Solution:

To solve this problem, we work from the known specie to the unknown.

From the mass of the FeCl₃ given, we can solve for the number of moles of the unknown.

Number of moles of FeCl₃;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of FeCl₃ = 56 + 3(35.5) = 162.5g/mol

Number of moles = $\frac{100}{162.5}$ = 0.62mole

From the reaction expression;

2 mole of FeCl₃ is produced from 3 moles of Cl₂

0.62 mole of FeCl₃ will be produced from $\frac{0.62 x 3}{2}$ = 0.92mole

The number of moles of Cl₂ = 0.92moles

5 0

3 years ago

Which of these is an example of a physical change?

Vikki [24]

Answer:

b metal denting

Explanation:

8 0

4 years ago

Read 2 more answers

. A compound contains only C, H, N, and O. It contains 37.0 % C and 42.5% O (both by mass), and there are 2 O atoms for every 1

jasenka [17]

Answer:

C₂₁H₁₅N₉O₁₈

Explanation:

Molecular formula is the ratio of atoms that are present in 1 molecule of the compound. We need to find moles of all atoms to find this ratio.

In a basis of 100, moles of C and O are:

Moles C:

37.0 * (1mol / 12g) = 3.083 moles C

Moles O:

42.5g * (1mol / 16) = 2.656 moles O

Now, to find moles of H, we need determine moles of H2O produced:

0.0310g H2O * (1mol / 18g) = 1.72x10⁻³ moles H2O * 2 = 3.44x10⁻³ moles H

These moles were produced when 0.157g of the compound react. In a basis of 100g:

3.44x10⁻³ moles H * (100g / 0.157g) = 2.194 moles H

In the same way, moles of N are:

0.0230g NH3 * (1mol / 17g) = 1.35x10⁻³ moles H2O

These moles were produced when 0.103g of the compound react. In a basis of 100g:

1.35x10⁻³ moles H * (100g / 0.103g) = 1.313 moles N

Empirical formula is (The simplest whole number ratio of atoms presents in a molecule). Dividing in the low number of moles (Moles N):

C: 3.083 moles C / 1.313 moles N = 2.3

O: 2.656 moles O / 1.313 moles N = 2.0

N: 1.313 moles N / 1.313 moles N = 1

H: 2.194 moles H / 1.313 moles N = 1.67

This ratio times 3 (To have the whole number ratio):

C: 7

O: 6

N: 3

H: 5

The empirical formula is:

C₇H₅N₃O₆

And weighs:

C: 7*(12g/mol)= 84

H: 5 * (1g/mol) = 5

N: 3 * (14g/mol) = 42

O: 6* (16g/mol) = 96

227g/mol

As the molecular mass of the compound is 681g/mol:

681 / 227 = 3

The empirical formula times 3 is the molecular formula, that is:

C₇H₅N₃O₆ × 3

4 0

3 years ago