Molar mass
H2S = 34.0 g/mol
O2 = 31.99 g/mol
S8 = 256.52 g/mol
Identifying excess reagent and the limiting of the reaction :
8 H2S(g) + 4 O2(g) = S8(I) + 8 H2O(g)
8 x 34 g H2S --------> 256. 52 g S8
35.0 g ----------------> ??
35.0 x 256.52 / 8 x 34 =
8978.2 / 272 => 33.00 g of S8
H2S is the limiting reactant
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4 x 31.99 g O2 --------------- 256.52 g S8
40.0 g O2 --------------------- ??
40.0 x 256.52 / 4 x 31.99 =
10260.8 / 127.96 = 80.16 g of S8
O2 is the excess reagent is the excess <span>reagent
</span>
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H2S is the limiting reactant, one that is fully consumed, it is he who determines the mass of S8 produced
33.0 g ----------- 100%
?? g ------------- 95 %
95 x 33.00 / 100 => 31.35 g
hope this helps!
The genetic variation would decrease or stay the same. the offspring of the organisms that are repopulating with mate with each other because those are the only same organisms around ( low key gross but it's true)
Yes layers of sediment form at the bottom of the ocean.
Answer: The new pressure is 3 psi.
Explanation:
Given: 
= 12 psi, 
= ?, 
Formula used is as follows.
Thus, we can conclude that the new pressure is 3 psi.
40g! sorry if i’m wrong!!
