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Sveta_85 [38]
3 years ago
13

SOMEONE HELP QUICK PLSwhat are ways significant digits can be used in the real world

Chemistry
1 answer:
damaskus [11]3 years ago
3 0
Science, Economics, Statistics, Finance, and many other areas of life where we are measuring things to a certain level of accuracy.
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Which of the following is ONE of the signs of a chemical change
pickupchik [31]

Answer:

um i one of what?

Explanation:

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3 years ago
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What is the mass of an osmium block that measures 6.70 cm × 9.20 cm × 3.30 cm? The density of osmium is given as 22.610 g/cm3. N
alexira [117]

Answer:

m= 4,599.145 g

Explanation:

Let m = mass, d = density and V = volume of the osmium block.

m = d x V

m = 22.610 g/cm3 x (6.70 x 9.20 x 3.3) cm3

m = 4,599.145 g

7 0
3 years ago
What will be the final temperature of the solution in a coffee cup calorimeter if a 50.00 mL sample of 0.250 M HCl(aq) is added
padilas [110]

Answer:

21.21°C will be the final temperature of the solution in a coffee cup calorimeter.

Explanation:

HCl+NaOH\rightarrow H_2O+NaCl

\Delta H = enthalpy change = -57.2 kJ/mol of NaOH

Moles of sodium hydroxide = n

Molarity of the NaOH = 0.250 M

Volume of NaOH solution = V = 50.00 mL = 0.050 L

n=Molarity\times V=0.250 M\times 0.050 L= 0.0125 mol

Moles of HCl = n'

Molarity of the HCl= 0.250 M

Volume of HCl solution = V' = 50.00 mL = 0.050 L

n'=Molarity\times V=0.250 M\times 0.050 L= 0.0125 mol

Since 1 mole of Hcl reacts with 1 mole of NaoH. Then 0.0125 mole of HCl will react with 0.0125 mole of NaOH.

The enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

q=\Delta H\times n=-57.2 kJ/mol \times 0.0125 mol= -0.715 kJ=-715 J

q = heat released on reaction= -715 J

now, we calculate the heat gained by the solution.:

Q= -q = -(-715 J) = 715 J

m = mass of the solution = ?

Volume of the solution formed by mixing, v = 50.00 ml + 50.00 mL = 100.00 mL

Density of the solution = density of water = d = 1 g/mL

mass=density\times volume=d\times v=1 g/ml \times 100.00 ml=100 g

m = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{f} = final temperature = ?

T_{i} = initial temperature = 19.50^oC

Q=mc\times (T_{f}-T_{i})

Now put all the given values in the above formula, we get:

715 J=100 g\times 4.18J/^oC\times (T_f-19.50)^oC

T_f=21.21 ^oC

21.21°C will be the final temperature of the solution in a coffee cup calorimeter.

5 0
3 years ago
How many molecules are in 643.21 grams of Mg3(PO4)2?
Eva8 [605]

Answer:

643.21g  1 mol  6.022^23

262.87 g   1 mol

= 1.4735E24     [Mg3(PO4)2]

4 0
2 years ago
Bluebirds and blue jays, two bird species live in a small wooded area. The blue jays are very aggressive and eventually take ove
Dahasolnce [82]

Answer:

yes

Explanation:

it affects the bluebirds habitat

5 0
3 years ago
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