Question

How any moles of H2O will be produced from 12.3 moles of HCL reacting with Ca(OH)2?

Answer 1

Answer:

\large \boxed{\text{12.3 mol HCl}}  

Explanation:

We need a balanced chemical equation with moles.

            2HCl +Ca(OH)₂ ⟶ CaCl₂ + 2H₂O

n/mol:    12.3

The molar ratio is 2 mol H₂O:2 mol HCl.

$\text{Moles of H _{2} O} = \text{12.3 mol HCl} \times \dfrac{\text{2 mol H _{2} O}}{\text{2 mol HCl}} = \textbf{12.3 mol HCl}\\\\\text{The reaction produces \large \boxed{\textbf{12.3 mol HCl}} }$