There are 5.66 moles of hydrogen in the sample of talc(hydrated magnesium silicate).
Given,
Talc formula is 
moles of magnesium = 8.5 moles
The stoichiometry of magnesium and hydrogen is 3 : 2,
So 3 moles of magnesium is equivalent to 2 moles of hydrogen.
Then 8.5 moles of magnesium is equivalent to
=5.6666 moles
<h3>Talc </h3>
Talc(hydrated magnesium silicate), often known as talcum, is a type of clay mineral made up of hydrated magnesium silicate, having the formula Mg3Si4O10(OH)2. Baby powder is made of powdered talc, frequently mixed with corn starch. This mineral serves as a lubricant and thickening agent. It serves as a component in paint, pottery, and roofing materials. It serves as a key component in many cosmetics. It can be found as foliated to fibrous aggregates and in a remarkably uncommon crystal form. It is foliated with a two-dimensional platy form, has a flawless basal cleavage, and an irregular flat fracture.
Talc(hydrated magnesium silicate), the softest mineral, is assigned a value of 1 on the Mohs scale of mineral hardness, which is based on scratch hardness comparisons.
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Answer:
O.1M
Explanation:
First let's generate a balanced equation for the reaction
NaOH + HCl —>NaCl + H2O
From the equation,
The ratio of the acid to base is 1:1.
From the question, we obtained the following:
Ma = Molarity of acid = 0.12M
Va = volume of acid = 21.35cm3
Vb = volume of base = 25.55cm3
Mb = Molarity of base =?
We obtained nA(mole of acid) and nB(mole of base) to be 1
The molarity of the base can be calculated for using:
MaVa/ MbVb = nA / nB
0.12x21.35 / Mb x 25.55 = 1
Cross multiply to express in linear form
Mb x 25.55 = 0.12x21.35
Divide both side by 25.55
Mb = (0.12x21.35) / 25.55
Mb = 0.1M
The molarity of the base is 0.1M
Answer:
When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K
Explanation:
Step 1: Data given
A sample of sulfur hexafluoride gas occupies a volume of 5.10 L
Temperature = 198 °C = 471 K
The volume will be reduced to 2.50 L
Step 2 Calculate the new temperature via Charles' law
V1/T2 = V2/T2
⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L
⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K
⇒with V2 = the reduced volume of the gas = 2.50 L
⇒with T2 = the new temperature = TO BE DETERMINED
5.10 L / 471 K = 2.50 L / T2
T2 = 2.50 L / (5.10 L / 471 K)
T2 = 230.9 K = -42.1
When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K
Answer: Option A. 6.022 x 10^23
Explanation: