The anode is the electrode where the oxidation occurs.
Cathode is the electrode where the reducction occurs.
Equations:
Mn(2+) + 2e- ---> Mn(s) Eo = - 1.18 V
2Fe(3+) + 2e- ----> 2 Fe(2+) 2Eo = + 1.54 V
The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.
Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72
Answer: 2.72 V
Answer:
C. porous
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Things go sublime when changing automatically into vapor when it is heated, usually forming a solid figure.
Answer:
You subtract the atomic number from the mass number to find the number of neutrons. If the atom is neutral, the number of electrons will be equal to the number of protons.
Answer:
Explanation:
Hello,
In this case, the rate is computed as:
As the reaction is analyzed during the first 30 seconds, the average rate will be:
Which negative since the cupric chloride is a reagent.
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