If an atom of sodium had an atomic number of 11, and lost and electron , what would you have?

1 answer:

3 0

The atomic number of an element tells you how many protons each atom has. Losing an electron won't affect the number of protons. It will, however, change the charge on the atom. Protons are positive and electrons are negative. If there's more positive than negative then the atom has a positive charge. So the charge for the sodium atom would be +1

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joja [24]

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(a) Increasing the temperature adds heat which is a reactant shifting the equilibrium rightwards.

(b) Pressure has no effect since the change in the number of moles is zero.

Explanation:

Hello,

In this case, one could represent the given reaction as:

$N_2(g)+O_2(g)+ \Delta _rH \leftrightarrow 2NO$

Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.

Furthermore, for the (b) statement, since the change in the number of moles is zero, based on the stoichiometric coefficients as shown below:

$\Delta \nu =2-1-1=0$