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lesya692 [45]
3 years ago
14

The formula for the nitrate ion: NO3 NO2 NO3+​

Chemistry
2 answers:
Leviafan [203]3 years ago
5 0

no3-Edg 2020

Explanation

Brainliest

tekilochka [14]3 years ago
3 0

Answer:

NO3-

Explanation:

edge2020

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How many atoms are in 3Mg(OH)2
Neko [114]

Answer:3 atoms of Mg 6 atoms of O and 6 atoms of H

Explanation:

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How many moles of ScCl3 can be produced when 10.00 mol Sc react with 9.00 mol Cl2
Nuetrik [128]

Answer:

Moles of ScCl_3 = 6 moles

Explanation:

The reaction of Sc and Cl_2 to make ScCl_3 is:

2Sc+3Cl_2⇒2ScCl_3

The above reaction shows that 2 moles of Sc  can react with 3 moles of Cl_2 to form ScCl_3.

Mole Ratio= 2:3

For 10 moles of Sc we need:

Moles of Cl_2 = Moles of Sc *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 = 10 *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 =15 moles

So 15 moles of Cl_2 are required to react with 10 moles of Sc but we have 9 moles of Cl_2 , it means Cl_2 is limiting reactant.

Moles of ScCl_3=Given\  Moles\  of\ Cl_2 *\frac{2\  Moles\ o\ fScCl_3}{3\ Moles\ of\ Cl_2}

Moles\ of\  ScCl_3=9 *\frac{2\  Moles\ of\ ScCl_3}{3\ Moles\ of\ Cl_2}

Moles of ScCl_3= 6 moles

4 0
2 years ago
Read 2 more answers
True or False: A property is a way to
kenny6666 [7]

Answer:

True

Explanation:

Here is an example: chemical properties include flammability, toxicity, acidity, reactivity. we observe the changes of these properties. Therefore, It's true.

5 0
2 years ago
8 Write the equation
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Answer:

Explanation — This page looks at the oxidation of alcohols using acidified sodium or ... of sodium or potassium dichromate(VI) acidified with dilute sulfuric acid. ... The electron-half-equation for this reaction is as follows: ... To do that, oxygen from an oxidizing agent is represented as [O]. ... Article type: Section or Page.

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sukhopar [10]
Gay-Lussac's law gives the relationship between pressure and temperature of a gas.
it states that for a fixed amount of gas of constant volume pressure is directly proportional to temperature. 
P/T = k
where P - pressure, T - temperature and k - constant 
\frac{P1}{T1} =  \frac{P2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
temperature should be in the kelvin scale,
T1 = 22 °C + 273 = 295 K
substituting the values in the equation 
\frac{1.20atm}{295 K}  =  \frac{2.00 atm}{T}
T = 492 K
new temperature - 492 - 273 = 219 °C
5 0
3 years ago
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