Answer:
(1) cathode: Y
(2) anode X
(3) electrons in the wire flow toward: Y
(4) electrons in the wire flow away from: X
(5) anions from the salt bridge flow toward X
(6) cations from the salt bridge flow toward Y
(7) gains mass: Y
(8) looses mass X
Explanation:
The voltaic cell uses two different metal electrodes, each in an electrolyte solution. The anode will undergo oxidation and the cathode will undergo reduction. The metal of the anode will oxidize, going from an oxidation state of 0 (in the solid form) to a positive oxidation state, and it will become an ion. At the cathode, the metal ion in the solution will accept one or more electrons from the cathode, and the ion’s oxidation state will reduce to 0. This forms a solid metal that deposits on the cathode. The two electrodes must be electrically connected to each other, allowing for a flow of electrons that leave the metal of the anode and flow through this connection to the ions at the surface of the cathode. This flow of electrons is an electrical current that can be used to do work, such as turn a motor or power a light.
Answer:
0.08 moles
Explanation:
Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158
=> Moles in 13g of KMnO4 = 
= 
= 0.082278.. = 0.08 moles
The last answer
the place where the organisms live
Hope this helps!!! :))))
The answer would be B.
U-238 has a n to p ration of 1.6:1. 146 neutrons and 92 protons.
It is actually the most commonly used isotope is reactors.
C-14 is also a radioactive isotope with 8 neutrons and 6 protons.
The usual and ideal n to p ratio is 1:1 such as C-12 or Mg-24
Answer:
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In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.
Explanation:
