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sertanlavr [38]
2 years ago
14

What volume, IN MILLILITERS, of 5.0M HCl solution is required to react with 3.00 g or magnesium metal?

Chemistry
1 answer:
siniylev [52]2 years ago
3 0

The volume of HCl = 2.10⁴ mL

<h3>Further explanation</h3>

Given

5.0 M(mol/L) HCl solution

3 g of Mg

Required

Volume of HCl

Solution

Reaction

Mg + 2HCl ⇒ MgCl₂ + H₂

mol of Mg (Ar=24 g/mol) :

mol = mass : Ar

mol = 3 : 24

mol = 0.125

From the equation, mol ratio of Mg : HCl = 1 : 2, so mol HCl :

= 2/1 x mol Mg

= 2 x 0.125

= 0.25

Molarity : mol solute per liters solution

M = m x V

V = M : m

V = 5 mol/L : 0.25

V = 20 L = 2.10⁴ mL

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german

Order of metals from least reactive to most reactive: B <C <A <D

<h3>Further explanation</h3>

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

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II. When A is added to solutions of the other metal ions, metallic B and C are  formed but not D.

This means that metal A is more reactive than metals B and C, while D is more reactive than A, so metal D is the most reactive

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