Find the volume of a rock made out sandstone with a density of 2.4 g/cm^3 and a mass of 8.5g.

what Is the number of photons in one J of red light (650 nm) greater than, equal to, or less than the number of photons in one J

valentinak56 [21]

For the same amount of energy, the number of photons in red light will be greater than the number of photons in blue light.
This is because the energy carried by a photon is inversely proportional to the wavelength of the photon. A longer wavelength means there is a lower energy in the photons and a shorter wavelength means that there is a higher energy. Therefore, in order for the photons to deliver one joule of energy, more of the red light photons will be required.

7 0

3 years ago

An element has an atomic number of 80. How many protons and electrons are in an atom of the element?

Nadya [2.5K]

80 protons,121 Neutrons, and 80 electrons the element is Mercury

6 0

3 years ago

β‑Galactosidase (β‑gal) is a hydrolase enzyme that catalyzes the hydrolysis of β‑galactosides into monosaccharides. A 0.387 g sa

gtnhenbr [62]

Answer:

The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=icRT$

where,

$\pi$ = osmotic pressure of the solution = 0.602 mbar = 0.000602 bar

0.000602 bar = 0.000594 atm

(1 atm = 1.01325 bar)

i = Van't hoff factor = 1 (for non-electrolytes)

c = concentration of solute = ?

R = Gas constant = $0.0820\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273.15 +25]=298.15 K$

Putting values in above equation, we get:

$0.000594 atm=1\times c\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298.15 K\\\\c=2.4278\times 10^{-5} mol/L$

The concentration of solute is $2.4278\times 10^{-5} mol/L$

Volume of the solution = V =0.137 L

Moles of β‑Galactosidase = n

$C=\frac{n}{V(L)}$

$n=2.4278\times 10^{-5} mol/L\times 0.137 L$

$n=3.3261\times 10^{-6} mol$

To calculate the molecular mass of solute, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of β‑Galactosidase = $3.3261\times 10^{-6} mol$

Given mass of β‑Galactosidase= 0.387 g

Putting values in above equation, we get:

$3.3261\times 10^{-6} mol =\frac{0.387 g}{\text{Molar mass of solute}}\\\\\text{Molar mass of solute}=116,352.97 g/mol$

Hence, the molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

3 0

2 years ago

A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?

Colt1911 [192]

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

V₁T₂=V₂T₁

Where in this case:

V₁ = 852 mL

T₂ = 200 K

V₂ = ?

T₁ = 298 K

We input the data:

852 mL * 200 K = V₂ * 298 K

And solve for V₂:

V₂ = 571.81 mL

The new volume would be 571.81 mL.

4 0

3 years ago

Which of the following soils is the most porous? Soil A - flat, sorted particles. Soil B - round, sorted particles Soil C - roun

Ksju [112]

Answer: Option (b) is the correct answer.

Explanation:

Porosity means the ease with which a fluid can pass through between a rock or cracks etc.

If particles of a soil are flat and even if they are sorted then there will rarely be any space available for fluid or water to pass through it.

If soil particles are round in shape and are sorted then there will be space available for the fluid to pass through it. Hence, this type of soil will be most porous.

Similarly, if soil particles are round but are unsorted then there will be less space available as compared to sorted particles. This is because particles are placed randomly so, somewhere there will be much less space and somewhere there will be large space available. As a result, soil will not be most porous.

If soil particles are flat and unsorted then there will also be less space available for the fluid to pass through it. Thus, soil will be less porous.

Hence, we can conclude that out of the given options, soil B - round, sorted particles is the most porous.

4 0

3 years ago