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Andrej [43]
4 years ago
15

Calculate the molarity of 0.50 mol MgCl2 in 750 ml of solution.

Chemistry
2 answers:
ddd [48]4 years ago
8 0
Molarity = mol/L

0.50 mol of MgCl2
0.750 L (1000 mL = 1 L)

Molarity = 0.5 mol/0.75 L = 0.666667 M
Vedmedyk [2.9K]4 years ago
4 0

Answer : The correct answer for molarity of MgCl₂ solution is 0.67 M.

Molarity :

It expresses concentration of any solution . It can be defined as mole of solute present in volume of solution in Liter .

It uses unit M or \frac{mol}{L}

It can be formulated as :

Molarity (\frac{mol}{L} ) = \frac{mole of solute (mol)}{volume of solution (L)}

Given : mol of MgCl₂ (solute ) = 0.50 mol

Volume of solution = 750 mL

Following steps can be done :

Step 1 ) To convert volume of solution from mL to L

1 L = 1000 mL

Volume of solution = 750 mL * \frac{1 L}{1000mL}

Volume of solution = 0.750 L

Step 2) To find molarity

Plugging mole of solute and volume of solution in molarity formula as :

Molarity = \frac{0.50 mol}{0.750 L }

Molarity = 0.67 \frac{mol}{L}

Hence molarity of MgCl₂ solution is 0.67 M

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FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

  • FeBr₃

211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

\tt n=\dfrac{mass}{MW}\\\\n=\dfrac{211}{295,56}\\\\n=0.714

  • Na₂S

186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :

\tt n=\dfrac{186}{78.0452}=2.38

Coefficient ratio from the equation FeBr₃ :  Na₂S = 2 : 3, so mol ratio :

\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793

So  FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

\tt \dfrac{6}{3}\times 0.714=1.428

6 0
3 years ago
Name an element in the third period (row) of the periodic table with a total of 4 3p electrons
Wittaler [7]

Answer:

sulfur

Explanation:

sulfur has 4p electrons.

phosphorus has 3p electrons.

The question is asking which one has 4

3 0
3 years ago
The compound H2O is an example of a(n)
SashulF [63]
The answer you are looking for is water.
5 0
4 years ago
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For the chemical reaction , I identify the reactant and the products .
svetlana [45]

The reactant is Mercury (II) Oxide while the products are Mercury and Oxygen separately.

This is because the reactants are typically always on the left side of the yields symbol. In this decomposition reaction, it would still be the same as at the end of the reaction, there were to products produced: Mercury and Oxygen.

Products tend to always be on the right side of the yields symbol, they're what comes out of a reaction no matter what type.

Hope this helps!

7 0
4 years ago
What is the molecular formula for a compound that is 44.87% potassium, 36.7%
Phoenix [80]

Answer:

Molecular formula: S4K8O16  empirical formula: SK2O4

Explanation:

First we find the moles of each by first finding grams (using the percent) and then using stoichiometry to convert into moles:

Sulfur: 696 *.18 = 125.28grams S* \frac{1 mole S}{32.065 g S} = 3.907 moles S

Potassium: 696 *.4487 = 312.2952 *\frac{1 mole K}{39.08 g K}= 7.99117 mole K

Oxygen: 696 * .367 = 255.432 * \frac{1 mol O}{16g O} = 15.9654 mole O

Then we divide each value by the atom with the smallest number of moles to find the mole ratio:

3.907/3.907= 1

7.99117 mole K/ 3.907= 2.043

15.9654 mole O/ 3.907= 4.08

The empirical formula is SK2O4

To find the molecular formula, we divide the mass given (696) by the mass of the empirical formula (174.22) to get 4. We then divide each atom by 4.

Molecular formula: S4K8O16

5 0
3 years ago
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