Answer: 0.9375 g
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of
solution = 0.75 M
Volume of
solution = 25.0 mL = 0.025 L
Putting values in equation 1, we get:
According to stoichiometry :
2 moles of
require = 1 mole of
Thus 0.01875 moles of
will require=
of
Mass of
Thus 0.9375 g of
is required to react with 25.0 ml of 0.75 M HCl
Answer:
C6H14 < C6H13Br < C6H13OH < C6H12(OH)2
Explanation:
Hello,
In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:
C6H14 < C6H13Br < C6H13OH < C6H12(OH)2
Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.
Best regards.
I believe the statement is true. The heat transfer involved here is called conduction. It is one type of heat transfer where it caused by the collisions of the particles in a certain body. As the you add heat to the object, the kinetic energy of the molecules increases therefore more collisions could happen which would mean energy is dissipated or transferred from molecule to molecule.<span />
<u>Solution</u> : Emperical Formula = 
Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.
In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.
Given : 80.0g Carbon
20.0g Hydrogen
First convert the given masses into moles.


Value of each mole divided by the smallest number of moles and then round off.
Moles ratio of the element are


This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.
Emperical Formula = 