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never [62]
4 years ago
14

Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH-] is 1 x 10-2 mol/L. Is this solution acidid

c, basic, or neutral? Show your work.
Chemistry
1 answer:
Lilit [14]4 years ago
6 0

Answer:

[H⁺] = 1.0 x 10⁻¹² M.

Explanation:

<em>∵ [H⁺][OH⁻] = 10⁻¹⁴. </em>

[OH⁻] = 1 x 10⁻² mol/L.

∴ [H⁺] =  10⁻¹⁴/[OH⁻] = (10⁻¹⁴)/(1 x 10⁻² mol/L) = 1.0 x 10⁻¹² M.

∵ pH = - log[H⁺] = - log(1.0 x 10⁻¹² M) = 12.0.

∴ The solution is basic, since pH id higher than 7 and also the  [OH⁻] > [H⁺].

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SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

6 0
3 years ago
Arrange the following substances in order of increasing solubility of water. C6H14, C6H13Br, C6H13OH, C6H12(OH)2.
Juli2301 [7.4K]

Answer:

C6H14 < C6H13Br  < C6H13OH < C6H12(OH)2

Explanation:

Hello,

In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:

C6H14 < C6H13Br  < C6H13OH < C6H12(OH)2

Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.

Best regards.

5 0
3 years ago
Consute a tabela periódica e identifique o elemento químico ao qual corresponde cada item:
VMariaS [17]

Answer:

a

Explanation:

7 0
3 years ago
The end of the iron fire poker that you are holding gets warm even though it is not directly in the fire. The motion of the iron
AlladinOne [14]
I believe the statement is true. The heat transfer involved here is called conduction. It is one type of heat transfer where it caused by the collisions of the particles in a certain body. As the you add heat to the object, the kinetic energy of the molecules increases therefore more collisions could happen which would mean energy is dissipated or transferred from molecule to molecule.<span />
8 0
3 years ago
Read 2 more answers
A compound that is composed of only carbon and hydrogen contains 80.0% c and 20.0% h by mass. What is the empirical formula of t
gladu [14]

<u>Solution</u> : Emperical Formula =  CH_{3}

Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.

In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.

Given : 80.0g Carbon

            20.0g Hydrogen

First convert the given masses into moles.

80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}

20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}

Value of each mole divided by the smallest number of moles and then round off.

Moles ratio of the element are

\frac{6.66}{6.66}\text{mole of C}= 1

\frac{20.0}{6.66}\text{mole of C}= 3

This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.

Emperical Formula =  CH_{3}

3 0
4 years ago
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