Does water inside a vacuum boil at a higher or lower temperature than it does under normal pressures?

Chemistry

1 answer:

hammer [34]3 years ago

4 0

Answer:

lower temperature

Explanation:

When we boil water at vacuum, it boils at a lower temperature than the normal temperature

Boiling is defined as a physical phenomenon where bubbles are formed and they turn into vapor when the liquid is brought into heat.

The pressure is also decreased when water is heated under vacuum. The atmospheric pressure is reduced as the pressure is removed when water water boils at vacuum.

Thus, water inside vacuum boils at a lower temperature than it does under the normal pressure.

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The concentration of a biomolecule insdie a rod-shaped prokaryotic cell is 0.0051 M. Calculate the number of molecule inside the

Ann [662]

<u>Answer:</u> The number of molecules inside the cell are $2.2\times 10^6$

<u>Explanation:</u>

We are given a prokaryotic cell, which is in the shape of rod or cylinder.

The equation used to calculate the volume of cylinder is:

$V=\pi r^2h$

where,

V = volume of cell = ?

r = radius of the celle = $\frac{d}{2}=\frac{1.7\mu m}{2}=0.85\mu m=8.5\times 10^{-7}m$ (Conversion factor: $1m=10^6\mu m$ )

h = length of the cell = $3.1\mu m=3.1\times 10^{-6}m$

Putting values in above equation, we get:

$V=(3.14)\times (8.5\times 10^{-7})^2\times 3.1\times 10^{-6}\\\\V=7.033\times 10^{-18}m^3$

To calculate the number of moles for given molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of biomolecule = 0.0051 M

Volume of solution = $7.033\times 10^{-18}m^3=7.033\times 10^{-15}L$ (Conversion factor: $1m^3=1000L$ )

Putting values in above equation, we get:

$0.0051M=\frac{\text{Moles of biomoleculel}}{7.033\times 10^{-15}L}\\\\\text{Moles of biomolecule}=(0.0051mol/L\times 7.033\times 10^{-15}L)=3.59\times 10^{-17}mol$