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Igoryamba
2 years ago
8

What defines an element?

Chemistry
2 answers:
Troyanec [42]2 years ago
7 0

element is made up of only one type of atoms.

it is pure form of matter

example hydrogen, oxygen, carbon etc

Karolina [17]2 years ago
4 0

Answer:

An element is a substance that is made up of only one kind of atom and cannot be broken down into simpler forms by any ordinary chemical means

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What element is being oxidized<br><br> Fe2O3 + 3CO -&gt; 2FE +3C02
Vinvika [58]
Fe because oxidation mean loss of oxygen and Fe lose the oxygen so Fe is oxidised
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What is the molarity of a solution of 14.0 g NH4Br in enough H2O to make 150 mL of solution?
kiruha [24]
The molarity of a solution equals to the mole number of the solute/the volume of the solution. For NH4Br, we know that the mole mass is 98. So the molarity is (14/98) mol /0.15 L=0.95 mol/L.
8 0
3 years ago
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A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
DaniilM [7]
800 joules because it's twice the amount
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You need 270 ml of a 65% alcohol solution. on hand, you have a 90% alcohol mixture. how much of the 90% alcohol mixture and pure
olganol [36]

You must add 75 mL water to 195 mL 90 % alcohol to make 270 mL of 65 % alcohol.

<em>Step 1.</em> Calculate the volume of 90 % alcohol needed

You can use the dilution formula

<em>V</em>1×<em>C</em>1 = <em>V</em>2×<em>C</em>2

where

<em>V</em>1 and<em> V</em>2 are the volumes of the two solutions

<em>C</em>1 and <em>C</em>2 are the concentrations

You can solve the above formula to get

<em>V</em>2 = <em>V</em>1 × <em>C</em>1/<em>C</em>2

<em>V</em>1 = 270 mL; <em>C</em>1 = 65 %

V2 = ?; _____<em>C</em>2 = 90 %

∴<em>V</em>2 = 270 mL × (65 %/90 %) = 195 mL

You need 195 mL of 90 % alcohol to make 270 mL of 65 % RA

<em>Step 2</em>. Calculate the amount of water to add.

Volume of water = 270 mL – 195 mL = 75 mL

8 0
3 years ago
Consider the combustion of octane (C8H18)
sesenic [268]
The balanced equation for the above reaction is as follows;
2C₈H₁₈ + 25O₂ --->  16CO₂  + 18H₂O
stoichiometry of octane to CO₂ is 2:16
number of C₈H₁₈ moles reacted - 191.6 g / 114 g/mol = 1.68 mol
when 2 mol of octane reacts it forms 16 mol of CO₂
therefore when 1.68 mol of octane reacts - it forms 16/2 x 1.68 = 13.45 mol of CO₂
number of CO₂ moles formed - 13.45 mol
therefore mass of CO₂ formed - 13.45 mol x 44 g/mol = 591.8 g
 mass of CO₂ formed is 591.8 g
3 0
3 years ago
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