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3 years ago

39 - 7X = —4 ( 7X +7 ) + 4 - = minus sign — = negative sign

Mathematics

1 answer:

stepan [7]3 years ago

4 0

Answer:

x=-3

Step-by-step explanation:

39 - 7X = —4 ( 7X +7 ) + 4

Distribute

39 -7x = -28x -28 +4

Combine like terms

39 -7x =-28x -24

Add 28x to each side

39 -7x+28x =-28x+28x -24

39+21x=-24

Subtract 39 from each side

39-39+21x = -24 -39

21x = -63

Divide by 21

21x/21 = -63/21

x = -3

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?simplified the expression

larisa [96]

The first two negatives cancel out and you're left with positive 4. Now go inside the square root and do the exponent. -4*-4 = 16. Then do the -4*3*1 = -12. Do 16-12 = 4. now the square root of 4 = 2. at the dominator is 2*3 = 6. right now they problem should look like 4+- 2/ 6. from there you split the problem in two. so you have 4+2/6 & 4-2/6 then you solve both problems.
6/6 2/6
1 1/3
1 & 1/3 are your answers. I hope this helped!

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3 years ago

The spinner shown is divided into congruent sections that are labeled from 1 through 7. If the spinner is spun one time, what is

adoni [48]

Answer:

3/7

Step-by-step explanation:

The number of possible results are;

1, 2 , 3 , 4 , 5, 6 , 7 = 7

odd numbers here are;

1, 3 , 5 and 7

non-odd numbers are 2, 4 and 6

So the section not labeled with an odd number is 3

Hence the probability here is that;

3/7

4 0

3 years ago

Read 2 more answers

The cost of an item is 100% of its price what number place of? In the addition problem

yKpoI14uk [10]

I need the answer too. My brother needs it.

7 0

3 years ago

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

laila [671]

Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>

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3 years ago

If the area of a circle below is 18ft, what is the area of the shaded sector?

erik [133]

The Shaded area is .25 of the circle, so:

Area/4 = Shaded

18/4 = Shaded

4.5 = Shaded

Hope this helps!

8 0

4 years ago