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Natalka [10]
3 years ago
10

To frame a square piece of artwork such as a photo or print, a framing store bases it charge on the perimeter P, in inches, of t

he frame needed to surround both the artwork and a border around the artwork called a mat. A particular style of frame costs $1.50 per inch, while the glass costs $0.10 per square inch and the mat costs $0.15 per square inch. There is also a flat labor charge of $30. The total charge C for the framing is given by the function C(P) =1.5P+0.25(P4)2+30. In this function, what does the expression 0.25(P4)2represent?
Mathematics
1 answer:
nignag [31]3 years ago
6 0

Answer:

Step-by-step explanation:

To frame a square piece of artwork such as a photo or print, a framing store bases it charge on the perimeter P, in inches, of the frame needed to surround both the artwork and a border around the artwork called a mat. A particular style of frame costs $1.50 per inch, while the glass costs $0.10 per square inch and the mat costs $0.15 per square inch. There is also a flat labor charge of $30. The total charge C for the framing is given by the function C(P) =1.5P+0.25(P4)2+30. In this function, what does the expression 0.25(P4)2represent?

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Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

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and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

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3 years ago
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Step-by-step explanation:

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12,14y-8=13

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4 0
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Rcsc(theta) = 3
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