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Setler79 [48]
3 years ago
8

Mr. Arellano decided to make cookies for 7th grade students. He was supposed to mix 4 cups of flour, 1.2 cups of sugar, and 2.5

cups of chocolate chips to make 200 cookies, Mr. Arellano discovered the bag of flour he bought only has 2 cups of flour. How many cups of sugar and chocolate chips should Mr. Arellano use to keep the recipe proportional?
Mathematics
1 answer:
Ahat [919]3 years ago
8 0

Answer:

0.6 cups of sugar and 1.25 cups of chocolate chips

Step-by-step explanation:

We can begin to solve this problem with a simple proportion:

\frac{4}{2} = \frac{1.2}{x} = \frac{2.5}{y}

(x = the new # of sugar    y = new # of chocolate chips)

In order to keep everything proportional, we must abide by the scale factor shown with the the flour.

Basically, if we're going to use three times the amount of flour we actually need, then we need to triple all our other ingredients.

We can see that the scale factor is one half, so

x = 1.2 * 0.5

and

y = 2.5 * 0.5

This means that:

x = 0.6

y = 1.25

This means that he has to use 0.6 (or 3/5) cups of sugar and 1.25 (or 9/8) cups of chocolate chips.

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Which of the following must describe a irrational number? A. a number with a repeating or terminating decimal expansion B. a num
Olenka [21]

Answer:

D.

Step-by-step explanation:

A irrational number can be defined as those numbers which are real but can NOT be expressed in simple fractions. The term 'irrational' means 'a number which can not be expressed in ratio of two integers', 'no ratio.'

<u>When a irrational number is expressed in decimal, the numbers keep on expanding without repeating andd without terminating, which means it keeps on expanding infinitely.</u>

For example, π (pi) is an irrational number. When it is expressed in decimals it keeps on expanding non-repeatedly and unendingly.

Another example of an irrational number is √2.

Thus the correct statement that defines irrational number is option D.

5 0
3 years ago
Joe has 37 coins consisting of nickels, dimes, and quarters. There are four more nickels than dimes and two more quarters than n
astraxan [27]

Answer:

  15

Step-by-step explanation:

Let n, d, q represent the numbers of nickels, dimes, and quarters. The problem statement tells us ...

  n +d +q = 37

  n = d +4

  q = n +2

___

Rearranging the second equation gives ...

  d = n -4

Substituting that into the first, we get ...

  n + (n -4) +q = 37

  2n +q = 41 . . . . . . . add 4 and simplify

Rearranging the third original equation gives ...

  n = q -2

Substituting into the equation we just made, we get ...

  2(q -2) +q = 41

  3q = 45 . . . . . . . . add 4 and simplify

  q = 15 . . . . . . . . . divide by 3

Joe has 15 quarters.

_____

<em>Check</em>

The number of nickels is 2 fewer, so is 13. The number of dimes is 4 fewer than that, so is 9. The total number of coins is 15 + 13 + 9 = 37, as required.

5 0
3 years ago
Solve the following equation, answer as a reduced, mixed number. Then place the correct number in the box provided. 4(7 - 3x) =
Luda [366]

Answer:  x = 0

<u>Step-by-step explanation:</u>

4(7 - 3x) = 7(4 - 2x)

28 - 12x = 28 - 14x        <em>distributed</em>

28 + 2x = 28                 <em>added 14x to both sides</em>

       2x = 0                    <em>subtracted 28 from both sides</em>

         x = 0                     <em>divided both sides by 2</em>

3 0
3 years ago
Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c
nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = \frac{81}{130} = 0.6231

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when M = 0.04

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.6231*0.3769}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.6231*0.3769}

\sqrt{n} = \frac{1.96\sqrt{0.6231*0.3769}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.6231*0.3769}}{0.04})^{2}

n = 563.8

Rounding up

We need a sample size of 564.

4 0
3 years ago
Anyone know what is 7(8+x+2)
Komok [63]

Answer: 7x + 70

Step-by-step explanation:

6 0
3 years ago
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