Answer: (A) vertical asymptote: x = 2, horizontal asymptote: y = 1
<u>Step-by-step explanation:</u>
<u>Vertical Asymptote</u> is the restriction on the x-value. The denominator cannot be zero, so x - 2 ≠ 0 ⇒ x ≠ 2
The restricted value on x is when x = 2 <em>which is the vertical asymptote</em>
<u>Horizontal Asymptote</u> (H.A.) is the restriction on the y-value. This is a comparison of the numerator (n) and denominator (m). There are 3 rules that will help you:
- n > m No H.A. (use long division to find slant asymptote)
- n = m H.A. is the coefficient of n divided by coefficient of m
- n < m H.A. is 0
In the given problem, n < m so y = 0, however there is also a vertical shift of up 1 so the H.A. also shifts up. This results in H.A. of y = 1
<span>Following BEDMAS
4[3+5(18/2-3)-12]+7^3
</span><span>= 4[3+5(18/-1)-12]+7^3
= </span>4[3+5(-18)-12]+ 343
= 4[3+(-90)-12]+ 343
= 4[3+(-90)-12]+ 343
= 4[-99]+ 343
= -396 + 343
= -53
Answer:
The two equations that can be used to find each of their ages are 
and 
.
Step-by-step explanation:
We are given that Mrs. Lang is 4 times as old as her daughter Jill. The sum of their ages is 60 years.
Let the age of Mrs. Lang be 'x years' and the age of her daughter Jill be 'y years'.
Now, according to the question;
- The <u>first condition</u> states that Mrs. Lang is 4 times as old as her daughter Jill, that means;
----------------- [equation 1]
- The <u>second condition</u> states that the sum of their ages is 60 years, that means;
{using equation 1}
y = 12 years
Now, putting the value of y in equation 1 we get;
= 48 years
Hence, the age of Mrs. Lang is 48 years and her daughter Jill is 12 years old.
Answer: (-4,-3)
Step-by-step explanation:
The answers is 4mm for the side length of the cube.
