Answer:
f(x) = x^3 - 2x^2 - x + 2
Step-by-step explanation:
since the zeroes are 1,-1, and 2. we can write the function like
f(x) = (x-1)(x+1)(x-2)
f(x) = (x^2-1)(x-2)
f(x) = x^3 -2x^2 -x +2
and it is true that f(0)=2
Answer:
2x^2 +2x-4
——————
2x^2-4x+2
Factor out 2 from the expression
2(x^2+x-2)
—————-
2(x^2-2x+1)
Write x as a difference
2(x^2x-x-2)
—————-
2(x^2-2x+1)
Use a^2-2ab+b^2=(ab)^2
2(x^2x-x-2)
—————-
2(x-1)^2
Reduce the fraction with 2
x^2x-x-2
—————-
(x-1)^2
Factor out x from the expression
X*(x^2)-x-2
—————-
(x-1)^2
Factor out negative sign from the expression
X*(x+2)-(x-2)
—————-
(x-1)^2
Factor out x+2 from the expression
(x+2)(x-1)
—————-
(x-1)^2
Simplify the expression
x+2
——
x-1
Answer:
Solution
Step-by-step explanation:
Hope this helped :)
Hi I don’t really understand can you explain a little bit please
