Question

Helppppp !!!

Answer 1

Answer:

x=-4 and x=1/2

Step-by-step explanation:

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2} +7x=4$  

equate to zero

$2x^{2} +7x-4=0$  

so

$a=2\\b=7\\c=-4$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(2)(-4)}} {2(2)}$

$x=\frac{-7(+/-)\sqrt{81}} {4}$

$x=\frac{-7(+/-)9} {4}$

$x=\frac{-7(+)9} {4}=\frac{1}{2}$

$x=\frac{-7(-)9} {4}=-4$

therefore

The solutions are

x=-4 and x=1/2