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loris [4]
3 years ago
11

Simplify the problem given.

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0
Step Number 1. is to Simplify \frac{4}{8}  to  \frac{1}{2}

Step Number 2. <span>Simplify so you get </span>\frac{x}{4} +  \frac{5}{3}

Done! :)
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Molly must drive across a bridge over a river eight times each week. Because the bridge is narrow and traffic is congested, Moll
oee [108]

Based on Molly's willingness to pay for the 8th trip, and the number of trips she can make over the bridge, her willingness to pay for the bridge repair would be<u> $1.00.</u>

<h3>What is Molly's willingness to pay for taxes to fix the bridge?</h3><h3 />

Molly's willingness to pay for trips is equal to the total consumer surplus she gets.

This means that her consumer surplus is $0.50.

With the bridge fixed, she can make 2 more trips than before because she can make 10 trips.

Her willingnesss to pay for the taxes will therefore be equal to her willingness to pay for the remaining trips:

= 0.50 x 2

= $1.00

Find out more on willingness to pay at brainly.com/question/8449170.

#SPJ1

8 0
2 years ago
Heeeeeelp plssssssss
victus00 [196]

Answer:

Your right?

Step-by-step explanation:

its the only answer that actually qualifies. Although any number above 20 would work I guess. there are no requirements.

4 0
3 years ago
Read 2 more answers
What is the area of the parallelogram?<br> 4cm 5cm 9cm
hammer [34]

Answer: Incomplete question, please edit.

Step-by-step explanation:

7 0
2 years ago
40081 in scientific notation
Maksim231197 [3]

4.0081 x 10 to the 4th power. I know because I did this one.

4 0
3 years ago
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















3 0
3 years ago
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