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3 years ago

An alloy consists of nickel, zinc, and copper in the ratio 2:7:9. How much alloy can be produced using 4.9 lb of zinc?

Mathematics

1 answer:

Wittaler [7]3 years ago

8 0

Ratio of Nickel to Zinc:

( 2/7 ) = ( Nickel /4.9)

Nickel = 1.4 lbs.

Ratio of Copper to Zinc:

( 9/7 ) = ( Copper /4.9)

Copper = 6.3 lbs.

Alloy = Zinc + Nickel + Copper

Alloy = 4.9 lbs. + 1.4 lbs. + 6.3 lbs.

Alloy = 12.6 lbs.

Hope this answer will be a good h<span>elp for you.</span>

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Please find the answer !

algol13

Answer:

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3 years ago

X is less than or equal to 9 and greater than or equal to 5

topjm [15]

5≤x≤9 it can also be reversed as 9≥x≥5 which is the same thing

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3 years ago

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A) is counting down by 3
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3 years ago

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom

gtnhenbr [62]

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x + 8

Expand the equation

x^2 + 6x + 8 = x^2 + 4x + 2x + 8

Factorize the equation

x^2 + 6x + 8 = (x + 2)(x + 4)

Hence, the signs in the binomials should be both positive

Read more about polynomials at:

brainly.com/question/4142886

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1 year ago

3+-√(-3)^2 - 4(5)(-1)

Alona [7]

Answer:

Step-by-step explanation:

Easy way to do this is step by step. Your quadratic, from your entry, must be

$5x^2-3x-1$ .

Step by step looks like this, one thing at a time:

$x=\frac{3+\sqrt{(-3)^2-4(5)(-1)} }{2(5)}$ becomes

$x=\frac{3+\sqrt{9-(-20)} }{10}$ becomes

$x=\frac{3+\sqrt{9+20} }{10}$

and this of course is

$x=\frac{3+\sqrt{29} }{10}$

Do the same with the subtraction sign to get the other solution.

If you're unsure of how to enter it into your calculator, do it step by step so you don't mess up the sign. If you enter it incorrectly, you could end up with an imaginary number when it should be real, or a real one that should be imaginary.

Just my advice as a high school math teacher.

3 0

3 years ago