If you form a triangle with the points B and C as two of the points of the right angled triangle then you use Pythagoras to find the length of BC.
3^2+4^2=25
√25 = 5
To get the result we have to find 20% of 22.58.
First we have convert 20% into decimal.
20% its 0.20
Finally we can multiply 0.2 and 22.58.
0.2*22.58=4.516 - its the answer
Below is the solution:
There are two equations to be solved here. The first one we assign variables to the home runs Peter hits, P, and Alice hits, A. P=2*(A-6) The second equation is the sum of both players home runs.P + A = 18Solving for P yieldsP=18-A We substitute the solution for P into the first equation and solve for A.(18-A) = 2*(A-6)18 - A = 2A - 123A = 30A = 10 Now that A is known, we can plug it into either equations for P to find how many home runs Peter hitsP=18 - (10) = 8orP=2((10)-4) = 8
Answer:
93.32% probability that a randomly selected score will be greater than 63.7.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected score will be greater than 63.7.
This is 1 subtracted by the pvalue of Z when X = 63.7. So



has a pvalue of 0.0668
1 - 0.0668 = 0.9332
93.32% probability that a randomly selected score will be greater than 63.7.