3 years ago

What can baby lizards do that baby snakes can't?

1 answer:

8 0

Grow their tails back because I had a pet lizard and then her tail got chopped off for a science experiment at school, and then in a few weeks, her tail grew back.

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Let the sequence {an} be defined so that a1 = 1 and each succeeding term is found by adding 3 to the one before it. Find the for

Sauron [17]

Answer:

Step-by-step explanation:

The sequence is arithmetic with n th term

$a_n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 1 and d = 3, thus

$a_{n}$ = 1 + 3(n - 1) = 1 + 3n - 3 = 3n - 2 → C

6 0

3 years ago

Find the distance between the points (-5,-7) and (4,-7)? PLS HELP GIVE BRAINLIEST

morpeh [17]

Answer:

Step-by-step explanation:

-7 and -7 are the same and -5 and 4 are 9 spaces apary.

Hope this helps plz hit the crown <3

8 0

3 years ago

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1. Convert 36 inches into feet. A. 3.5 ft B. B. 3 ft C. 2.5 ft D. 2 ft

deff fn [24]

The answer is Option B , the solution is 3

6 0

3 years ago

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What is this number written in standard form 3×1,000,00+3×100,00+2×100

pav-90 [236]

3(1,000,000)=3,000,000
3(100,000)=300,000
2(100)=200
3,300,200

6 0

3 years ago

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Find (f/g) (x) for the functions provided: ƒ(x) = x3 − 27, g(x) = 3x − 9

AnnZ [28]

Answer:

$(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)$

Step-by-step explanation:

We have been given that

$f(x)=x^3-27,g(x)=3x-9$

We can use the formula for difference of cubes to simplify the function f(x)

difference of cubes - $a^3-b^3=(a-b)(a^2+ab+b^2)$

$f(x)=x^3-27\\\\=x^3-3^3\\\\=(x-3)(x^2+3x+9)$

And g(x) can be written as

$g(x)=3x-9\\=3(x-3)$

Thus, we have

$(\frac{f}{g})(x)=\frac{(x-3)(x^2+3x+9)}{3(x-3}$

On cancelling the common factors, we get

$(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)$

5 0

3 years ago