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3 years ago

8/15 round the the third decimal in place

Mathematics

2 answers:

dalvyx [7]3 years ago

7 0

Answer:

0.533

Step-by-step explanation:

The full answer is 0.5333333333

But since you only need it rounded to the third decimal place, it can be rounded to 0.533

(3 is less than 5, so 3 does not need to be rounded to 4)

svetoff [14.1K]3 years ago

3 0

Answer: 0.533

Step-by-step explanation:

You could use a calculator.

8÷15=0.533333333...

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Complement of 0.7253

Nadya [2.5K]

Answer:

Step-by-step explanation:

if it is converting its 7253/10000

to percent 72.53

scientific notation is 7.253 *10-1 the -1 is on top of the 10

3 0

3 years ago

Melissa had 7 pages of homework! She only completed 5 before her soccer practice. Choose the division problem that shows what fr

disa [49]

Answer:

5/7

Step-by-step explanation:

if she had seven pages to do, and she only completes five, that means she completed 5 of the 7 of the problems. Another way to write this is 5 divide by 7 or 5/7.

7 0

3 years ago

Solve for x: 6 + 3x = x - 8

djyliett [7]

Answer:

x = 1 + i √ 2 , 1 − i √ 2

Step-by-step explanation:

7 0

3 years ago

Two numbers are in the ratio 3:8.<br> The larger number is 96, find the<br> sum of the numbers

zloy xaker [14]

Answer:

The sum of the numbers is <em>132</em>

Step-by-step explanation:

First find the smallest number

3/8=x/96
2(96)=8x
288=8x
x=36

Thus, you found the smallest number

then there sum given as 96+36=132

6 0

2 years ago

1+cos2A/cos2A = tan2A/tanA prove LHS=RHS

son4ous [18]

$RTP: \frac{1 + cos(2A)}{cos(2A)} = \frac{tan(2A)}{tan(A)}$

$LHS = \frac{1 + cos(2A)}{cos(2A)}$
$= \frac{1 + \frac{1 - tan^{2}(A)}{1 + tan^{2}(A)}}{\frac{1 - tan^{2}(A)}{1 + tan^{2}(A)}}$
$= \frac{\frac{1 + tan^{2}(A) + 1 - tan^{2}(A)}{1 + tan^{2}(A)}}{\frac{1 - tan^{2}(A)}{1 + tan^{2}(A)}}$
$= \frac{2}{1 - tan^{2}(A)}$
$= \frac{2}{1 - tan^{2}(A)} \cdot \frac{tan(A)}{tan(A)}$
$= \frac{\frac{2tan(A)}{1 - tan^{2}(A)}}{tan(A)}$
$= \frac{tan(2A)}{tan(A)}$
$= RHS$ , as required.

3 0

4 years ago