I need help with d please.

How do you write expression 5/6 using a fraction

Luden [163]

Answer:

5/6

Step-by-step explanation:

it is already written as a fraction.

do you mean as a decimal???

6 0

3 years ago

PART A: A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the tr

Greeley [361]

Complete Question:

Johnny printed two maps of a walking trail near his home. The length of the walking trail on the first map is 8 cm.

(a) Choose a length between 5 cm and 15 cm for the walking trail on the second map: ________cm.

(b) Determine the scale factor from the first map to the second map.

(c) A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the triangle landmark on the second map?

(d) Draw one of the triangles from part C. Label the side lengths and vertices accordingly. You may use this drawing tool or draw your triangle on paper:

Answer:

(a) Length = 4cm

(b) Scale factor = 0.5

(c) 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

Step-by-step explanation:

(a) Choose a length between 5 cm and 15 cm

$Length =4cm$ --- This is solely up to you (you can make use of any length between 5 cm and 15 cm)

(b) The scale factor

The scale factor (k) is calculated as:

$k = \frac{New\ Length}{Old\ Length}$

$k = \frac{4cm}{8cm}\\$

$k = 0.5$

(c) What are side lengths of 3 cm, 4 cm, and 5 cm on the second landmark

Using:

$k = \frac{New\ Length}{Old\ Length}$

The old lengths, in this case are: 3cm, 4cm and 5cm

Make New length the subject

$New\ Length = k * Old\ Length$

When $Length = 3cm$

$New\ Length = 0.5 * 3cm = 1.5cm$

When $Length = 4cm$

$New\ Length = 0.5 * 4cm = 2cm$

When $Length = 5cm$

$New\ Length = 0.5 * 5cm = 2.5cm$

So: 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

7 0

3 years ago

At winds speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 100

alisha [4.7K]

Answer:

Lower limit = 1007.95 cm/s

Upper limit = 1142.05 cm/s

Step-by-step explanation:

We have to calculate a 95% CI with population's standard deviation known.

The sample is size n=60, with mean M=1075.

The confidence interval can be expressed as:

$M-z*\sigma/\sqrt{n} \leq\mu\leq M+z*\sigma/\sqrt{n}$

For a 95% CI, the value of z=1.96.

$1075-1.96*265/\sqrt{60} \leq\mu\leq 1075+1.96*265/\sqrt{60} \\\\1075-67.05 \leq\mu\leq 1075+67.05\\\\ 1007.95 \leq\mu\leq 1142.05$

8 0

3 years ago

Help me pls with this question thank uuu

madam [21]

Let p be 2p and q be 3q. The ratio formed by this will be

$\sf \: p = 2 \\ \sf \: q = 3 \\ \sf \: p : q = 2 : 3$

Thus, Option A is the correct choice!!~

3 0

3 years ago

Combine the following fractions. a. 3/5 + 4/15 b. 5/6 - 1/4

Ne4ueva [31]

Hello there! :)

Answer:

1. $\boxed{\frac{13}{15} }$

2. $\boxed{\frac{7}{12} }$

Step-by-step explanation:

1. 3/5+4/15

First, you multiply by numerator and denominator.

3*3=9

5*3=15

$=\frac{9}{15}$

Then, you had to combine by the fractions.

$\frac{9}{15}+\frac{4}{15}$

Add by the numbers from left to right.

9+4=13

13/15 is the final answer.

______________________________________________

2. 5/6-1/4

First, you multiply by 2 both sides of numerator and denominator.

5*2=10

6*2=12

10/12

3/12

$\frac{10}{12}-\frac{3}{12}$

Subtract by the numerator.

10-3=7

7/12 is the final answer.

______________________________

Hope this helps!

Thanks!

Have a nice day! :)

:D

-Charlie

7 0

3 years ago