18 / 60 = 0.3
Charlie has completed 30% of his deliveries
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.
Find the median of the data (30.5)
Find the median of the lower half and the median of the upper half.
Subtract these two values.
The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
27.5 40.5
40.5-27.5 = 13
The interquartile range is 13.
Answer:
4 times as tall
hope this help:))
Answer:
a) There is no significant difference between the mean amounts charged
b) The skewness threatens the validity of the test
Step-by-step explanation:
<em>Given data:</em>
Group n x s
A 150 $1,987 $392
B 150 $2,056 $413
n1 = n2 = 150
x1 = 1987
x2 = 2056
s1 = 392
s2 = 413
∝ = 0.05
Attached below is the detailed solution