Find the median first.
78, 80, 83, 85, 86, 87, 90. The middle one is 85, so there's the median. Take the upper half of this set, not including the median, 85, and then subtract 86 from 90. This is 4, so this is the interquartile range.
SinA /a = sin C / c
sin 60/9 = sin C / 10
(√3/2)/9 = sinC/ 10
√3/18 = sin C / 10
so c will be sin inverse ((10√3)/10)
Answer:
3215
Step-by-step explanation:
There is no explanation
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The value of 3 in 630 is ten
