Answer:
x < - 6
Step-by-step explanation:
Given
4x + 8 < 1 +(2x - 5) ← remove parenthesis
4x + 8 < 1 + 2x - 5, that is
4x + 8 < 2x - 4 ( subtract 2x from both sides )
2x + 8 < - 4 ( subtract 8 from both sides )
2x < - 12 ( divide both sides by 2 )
x < - 6
Step-by-step explanation:
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So the waiting time for a bus has density f(t)=λe−λtf(t)=λe−λt, where λλ is the rate. To understand the rate, you know that f(t)dtf(t)dt is a probability, so λλ has units of 1/[t]1/[t]. Thus if your bus arrives rr times per hour, the rate would be λ=rλ=r. Since the expectation of an exponential distribution is 1/λ1/λ, the higher your rate, the quicker you'll see a bus, which makes sense.
So define <span><span>X=min(<span>B1</span>,<span>B2</span>)</span><span>X=min(<span>B1</span>,<span>B2</span>)</span></span>, where <span><span>B1</span><span>B1</span></span> is exponential with rate <span>33</span> and <span><span>B2</span><span>B2</span></span> has rate <span>44</span>. It's easy to show the minimum of two independent exponentials is another exponential with rate <span><span><span>λ1</span>+<span>λ2</span></span><span><span>λ1</span>+<span>λ2</span></span></span>. So you want:
<span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span></span>
where <span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span></span>.
Answer:
Step-by-step explanation:
13 = 5 + 5 + 3
Answer:
<h2>x = -8</h2><h2>y = 10</h2>
Step-by-step explanation:
Theoretically speaking, both equations need to equal 0.
Let's start with (x + 8)
x + 8 = 0
x = 0 - 8
x = -8
Then, let's go to (y - 10)
y - 10 = 0
y = 10 = 0
y = 10
So, x = -8 & y = 10
Hope that helps!
