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3 years ago

Which expression is equivalent to the given expression?

1 answer:

5 0

Assuming that the given expression is this one:
<span>−(12y+14)−(12y+14)

So, when you simplify it, you will get
- 24y - 28

It seems, that there is none in the following choices that is shown above satisfies the answer. Nevertheless, you just to add or subtract. Just remember the PEMDAS rule.</span>

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Solve:

svp [43]

568/800 is equal to 71%

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3 years ago

A manufacturing company makes 1125 items every hour. which or these statements are true ? Check all that apply

Inessa05 [86]

Answer:

I need to see the statements to answer your question

4 0

3 years ago

7. Which relation is a function?

Tamiku [17]

Answer:

D. relation is a function

hope this helps :-))

5 0

3 years ago

Read 2 more answers

Round 38562.7 to 1 significant figure

MissTica

= 488000
(real number)

= 4.88 × 105
(scientific notation)

<span>= 4.88e5

maybe this will help ?</span>

6 0

3 years ago

Read 2 more answers

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

5 0

3 years ago