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NeX [460]
3 years ago
11

Assume you measured <3 and <5 and found them to be equal. Use the spaces provided below to complete a formal proof that de

monstrates the picture is level with the trim.

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

1. S is a straight line that cuts through f and t

2. Given

3. ∠5 ≅ ∠7

4. ∠7 ≅ ∠3 Corresponding angles

Solution:

Step 1: Given

S is a straight line that cuts through f and t

Step 2: Given

∠3 ≅ ∠5

Alternate interior angles are equal.

Step 3: By Vertical angle theorem

Vertically opposite angles are congruent.

∠5 ≅ ∠7

Step 4: Corresponding angles

∠7 and ∠3 are corresponding angles.

∠7 ≅ ∠3

Step 5: Corresponding angles theorem

f || t

Hence proved.

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With a sample size of 200 adults what is probability that more than 35% have high blood pressure
ikadub [295]

Answer:

7

Step-by-step explanation:


4 0
3 years ago
Solve this system of equations algebraically: y x = 19 – x2 x y = 80 1. Isolate one variable in the system of equations. Y = –x2
miskamm [114]

System of equations helps to solve real-life problems. The system of equations will not have no solution.

<h3>What is a System of the equation?</h3>

Inconsistent System

A system of equations to have no real solution, the lines of the equations must be parallel to each other.

Consistent System

1. Dependent Consistent System

A system of the equation to be Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

A system of the equation to be Independent Consistent System the system must have one unique solution for which the lines of the equation must intersect at a particular.

The two of the system of equations given to us are,

y+x=19-x^2

x+y = 80

Now,

1. The first step is to isolate one variable in the system of equations,

y=19-x^2-x

y=80-x

2. The second step is to substitution to create a one-variable equation.

80-x=19-x^2-x\\x^2-x+x=19-80\\x^2 = -61

Now, since the value of x  is the negative square root. therefore, the system of equations will not have a real number of solutions.

If we plot the two equations on the graph, then the line of the system of equations will not intersect any point, therefore, the system of equations will have no solution.

Hence, the system of equations will not have no solution.

Learn more about the System of the equation:

brainly.com/question/12895249

6 0
3 years ago
FIRST ONE TO ANSWER GETS BRAINLIEST!!!!
-Dominant- [34]

Answer:

The maximum distance traveled is 4.73 meters in 0.23 seconds.

Step-by-step explanation:

We have that the distance traveled with respect to time is given by the function,

d(t) = 4.9t^2-2.3t+5.

Now, differentiating this function with respect to time 't', we get,

d'(t)=9.8t-2.3

Equating d'(t) by 0 gives,

9.8t - 2.3 = 0

i.e. 9.8t = 2.3

i.e. t = 0.23 seconds

Substitute this value in d'(t) gives,

d'(t) = 9.8 × 0.23 - 2.3

d'(t) = 2.254 - 2.3

d'(t) = -0.046.

As, d'(t) < 0, we get that the function has the maximum value at t = 0.23 seconds.

Thus, the maximum distance the skateboard can travel is given by,

d(t) = 4.9\times 0.23^2-2.3\times 0.23+5.

i.e. d(t) = 4.9\times 0.0529-2.3\times 0.23+5.

i.e. d(t) = 0.25921-0.529+5.

i.e. d(t) = 0.25921-0.529+5.

i.e. d(t) = 4.73021

Hence, the maximum distance traveled is 4.73 meters in 0.23 seconds.

5 0
3 years ago
The gradual wearing away or breaking down of rocks by abrasion is a type of blank weathering
grandymaker [24]
The correct answer that would best complete the given statement above would be PHYSICAL WEATHERING. The gradual wearing away or breaking down of rocks by abrasion is a type of physical weathering. In physical weathering, <span>rocks get smaller and smaller without a change in the composition of the rock.</span>
3 0
4 years ago
you are designing a poster that will be 3 yd wide and 8 ft high. How much paper do you need to make the poster
Lubov Fominskaja [6]
72 sq ft hope i could help all i did was turn them both into feet so nine and eight then multiply.
6 0
3 years ago
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