Answer:
7.06 x 10^(-7) ft 3
Step-by-step explanation:
We have the formula to calculate the volume of an octagonal Pyraamid as following:
<em>+) Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>
As given, the base of the pyramid is an octagon with area equal to 15mm2
=> Area of the base = 15 mm2
The height of the pyramid is the length of the line segment which is perpendicular to the base - which is the red line.
=> Height = 4mm
So we have:
<em>Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>
<em>= 1/3 * 15 * 4 = 20 mm3</em>
<em />
As: 1 mm3 = 3.53 x 10^(-8) ft 3
=> 20 mm3 = 7.06x10^(-7) ft 3
So the volume of the pyramid is : 7.06 x 10^(-7) ft 3
<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
Answer:
wgwagwagfwqgtfr3qt3qt432r43
Step-by-step explanation:
Given that:
f(1)=13 and 2f(n-1)+(n-2)
then:
f(4) will be found as follows:
f(2)=2f(2-1)=2f(1)=2*13=26
f(3)=2f(3-1)+(3-2)=2f(2)+1=2*26+1=53
f(4)=2f(4-1)+(4-2)=2f(3)+(4-2)=2(53)+2=108
Thus:
Answer:(3) 108
Answer:
Step-by-step explanation:
You draw a line right down the middle so it makes it to equal triangle
