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3 years ago

Cory found a job listed in a classified that pays a yearly salary of $54,013. What is the biweekly

Mathematics

1 answer:

Anon25 [30]3 years ago

5 0

Answer:

2077.42

Step-by-step explanation:

There are 52 weeks in a year, so there are 26 "biweekly" weeks in a year.

Cory receieves $54013 per year, so he gets 54013 / 26 dollars biweekly.

We can compute that number, getting 2077.42 dollars.

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What is the approximate volume of the composite figure? Use 22/7 for pi. Round to the nearest hundredth.

Temka [501]

Answer:

188.57 cm³

Step-by-step explanation:

Half sphere = 1/2 volume sphere

Sphere = 4/3 * 22/7 * 3³

Sphere = 4/3 * 22/7 * 27/1

Sphere = 2376/21 = 113.14

113.14 / 2 = 56.57

Cone = 22/7 * 3² * h/3

Cone = 22/7 * 9/1 * 14/3

Cone = 2772/21 = 132

132 + 56.57 = 188.57 cm³

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0

3 years ago

The data below gives the mean price (in cents) of a liter of regular gasoline at self-service filling stations at a sample of si

bogdanovich [222]

Answer:

135.05 ; 2.762 ; (133.201, 136.899) ; (132.840, 137.260)

Step-by-step explanation:

Given the data:

Urban area Price/liter

St. John, NL 137.1

Halifax 133.6

Montreal 136.2

Regina 132.3

Saskatoon 132.2

Yellowknife 138.9

Mean = (137.1 + 133.6 + 136.2 + 132.3 + 132.2 + 138.9) / 6

= 810.3 / 6

= 135.05

Standard deviation (σ) : √Σ(X - mean)²/n-1

(137.1 - 135.05)^2 + (133.6 - 135.05)^2 + (136.2 - 135.05)^2 + (132.3 - 135.05)^2 + (132.2 - 135.05)^2+ (138.9 - 135.05)^2 = 38.135

√(38.135 / (6 - 1))

= √7.627

= 2.7617023

= 2.762

C.)

90% confidence interval of the mean :

Mean ± Zcrit * σ/√n

Zcrit at 90% = 1.64

135.05 ± 1.64 * (2.762/√6)

135.05 ± 1.64 * 1.1275817

Lower Value = (135.05 - (1.64 * 1.1275817)) = 133.201

Upper Value = (135.05 + (1.64 * 1.1275817))) = 136.899

Confidence interval = (133.201, 136.899)

D.)

95% confidence interval of the mean :

Mean ± Zcrit * σ/√n

Zcrit at 95% = 1.96

135.05 ± 1.96 * (2.762/6)

135.05 ± 1.96 * 1.1275817

Lower Value = (135.05 - (1.96 * 1.1275817)) = 132.840

Upper Value = (135.05 + (1.96 * 1.1275817)) = 137.260

Confidence interval = (132.840, 137.260)

4 0

3 years ago

Simplify {n - 1 - [n - 1 - (n - 1)]}.

artcher [175]

Don't forget the invisble negative ones to distriute
do inside to outside

{n-1-1[n-1-1(n-1)]}
do inside
{n-1-1[n-1-n+1]}
simplify inner parenthasees
{n-1-1[n-n+1-1]}
{n-1-1[0]}
multply
{n-1-0}
add
n-1-0=n-1

it is n-1 simplified

4 0

4 years ago

Read 2 more answers

Jak mam uzbierać szybko na nowego Samsunga Galaxy s21+ bo potrzebuje jeszcze 2 900zł Pls szybko daje naj

MAVERICK [17]

Answer:

yesss queeen

Step-by-step explanation:

5 0

3 years ago

a person invest $1,700 in an account that earns 3.97% annual interest. find when the value of the investment reaches $3,200

olga_2 [115]

Answer:

16 1/4 years

Step-by-step explanation:

Assuming interest is compounded annually, the account balance (A) after t years will be ...

A = P(1 +r)^t

3200 = 1700·1.0397^t

log(3200) = log(1700) +t·log(1.0397)

t = (log(3200) -log(1700))/log(1.0397) ≈ 16.247

The account will reach a balance of $3200 after about 16 1/4 years.

___

You may be asked to round your answer to the nearest integer or tenth. We leave that exercise to the student.

5 0

4 years ago