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Natasha2012 [34]
3 years ago
15

Cory found a job listed in a classified that pays a yearly salary of $54,013. What is the biweekly

Mathematics
1 answer:
Anon25 [30]3 years ago
5 0

Answer:

2077.42

Step-by-step explanation:

There are 52 weeks in a year, so there are 26 "biweekly" weeks in a year.

Cory receieves $54013 per year, so he gets 54013 / 26 dollars biweekly.

We can compute that number, getting 2077.42 dollars.

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Question below. Please answer it, its math.
AleksAgata [21]

Answer:

- 0.8

Step-by-step explanation:

The first thing we want to do here is simplify the expression -

\frac{3}{5}( 2x + 5 ) - 2x, Distribute the " \frac{3}{5} " to elements within the parenthesis

= \frac{3}{5} * 2x + \frac{3}{5} * 5 - 2x, Focus on simplifying the expression " \frac{3}{5} * 2x + \frac{3}{5} * 5 "

= 2\cdot \frac{3}{5}x+5\cdot \frac{3}{5} - 2x

= \frac{6x}{5}+3 - 2x, Combine fractions

= -\frac{4x}{5} + 3

= -\frac{4}{5}x + 3

So we have our simplified expression "  -\frac{4}{5}x + 3, " with -\frac{4}{5} being the coefficient of x. Our requirements are that this fraction should be expressed as a decimal, so we can simply divide the numerator by the denominator to figure that out,

- 4 / 5 = - 0.8,

Solution = - 0.8

4 0
3 years ago
Does a plane have a definite beginning and end?
Lorico [155]
Technically no.  It extends forever in the X and Y axis, but does not have a Z axis.
5 0
3 years ago
Ivanna will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $40 and costs an a
natka813 [3]
First, let's make these two into equations.
The first plan has an initial fee of $40 and costs an additional $0.16 per mile driven.
Our equation would then be
C = 40 + 0.16m
where C is the total cost, and m is the number of miles driven.
The second plan has an initial fee of $51 and costs an additional $0.11 per mile driven.
So, the equation is
C = 51 + 0.11m
where C is the total cost, and m is the number of miles driven.
Now, your question seems to be asking for one mileage for both, equalling one cost. I would go through all the steps I've taken to try and find this for you, but it would probably take hours to type out and read. In short, I'm not entirely sure that an answer like that is possible in this situation, simply because of the large difference in the initial fee of the two plans, along with the sparse common multiples between the two mileage costs.
6 0
3 years ago
PLEASE HELP ASAP 25 POINTS GOOD ANSWERS ONLY!
timama [110]

Answer:

128

Step-by-step explanation:

6 0
3 years ago
PLZZZZ HELP WITH THIS QUESTION
Sauron [17]

A. 1/5 fish

We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5

Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.

So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15       3 ÷ 3 = 1 and 15 ÷ 3 = 5    3/15 = 1/5

1/5 of Mike's fish are damsel fish


B. 2/5 fish

Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.

First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5

Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish

And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5

8 0
3 years ago
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