Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
therer sorry for the cropped pic btw lol
Salutations!
12

- 9

=
Then,
- 9

-

Next, our final answer:
=

= 2
Our decimal would be 2.916667
Hopefully This Helps!!!
X-int: (square root of 31 + 6,0) & (square root of 31-6,0)
Y-int: (0,5)
Vertex: (6,-31)
AOS: x=6
Max/Min Value: (6,-31)