A square has an area of 42. What is the best estimate of the length of each side, to the nearest integer?

What is the slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of 34?

Alla [95]

One way to find the slope-intercept form is to plug the given values into point-slope form, y - y_{1} = m (x - x_{1}), where x_{1} and y_{1} are the coordinate points and m is the slope. Then, you solve for y.

y - y_{1} = m (x - x_{1}) Plug in the values
y - (-4) = 34 (x - 5) Fix the minus negative four
y + 4 = 34 (x - 5) Use the Distributive Property
y + 4 = 34x - 170 Subtract 4 from both sides
y = 34x - 174

The slope-intercept form of the equation that passes through (5, -4) and has a slope of 34 is y = 34x - 174.

6 0

3 years ago

jason spends 3.24 on 6 chocolate chip cookies. The cookies all cost the same amount. What is the cost of each cookie

Vlada [557]

Divide 3.24 with 6 and the answer will be found

$0.54

7 0

3 years ago

Read 2 more answers

Using the distance formula, calculate how far Tre threw the ball. (4 points: 2 points for setup, 1 for calculation, 1 for the an

sergij07 [2.7K]

Answer:

$D = 63.717$

Step-by-step explanation:

The details that complete the question are:

$(x_1,y_1) = (0,42.78)$

and

$(x_2,y_1)=(90,42.78)$

Required

Determine how far the ball travelled

Distance is calculated using:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute values for x's and y's

$D = \sqrt{(42.78 - 0)^2+(42.78-90)^2}$

$D = \sqrt{42.78^2+(-47.22)^2$

$D = \sqrt{1830.1284+2229.7284$

$D = \sqrt{4059.8568$

$D = 63.717$

Hence, the ball travelled a distance of 63.717 units

6 0

3 years ago

Giving 97 points for answer. Need asap for a, b, and c pls help.

Kay [80]

Answer:

sabi 97 tas 49 lang amp ginagawa mo

4 0

2 years ago

Read 2 more answers

An instructor in a college class recently gave an exam that was worth a total of 100 points. The instructor inadvertently made t

solniwko [45]

Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation = $\sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}$

Suppose,

X X - Xbar $(X - Xbar)^{2}$

3 3 - 6 = -3 -3 * -3 = 9

5 5 - 6 = -1 -1 * -1 = 1

10 10 - 6 = 4 4 * 4 = 16

Mean of above data, Xbar = $\frac{3+ 5+10}{3}$ = 6

Standard Deviation of data = $\sqrt{\frac{26}{3-1} }$ = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

X X - Xbar $(X - Xbar)^{2}$

3*2 = 6 6 - 12 = -6 -6 * -6 = 36

5*2 = 10 10 - 12 = -2 -2 * -2 = 4

10*2 =20 20 - 12 = 8 8 * 8 = 64

Mean of new data, Xbar = $\frac{6+ 10+20}{3}$ = 12

Standard Deviation of new data = $\sqrt{\frac{104}{3-1} }$ = 7.2111

Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as

3.6055 * 2 = 7.2111

Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.

8 0

3 years ago