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qaws [65]
4 years ago
14

Construct the resonance structure for CSO, which has a formal charge of +2 on the central atom and +1 on the oxygen atom.

Chemistry
1 answer:
CaHeK987 [17]4 years ago
4 0

Answer:

The given condition is proved.

Explanation:

Given that,

Construct the resonance structure for CSO, which has a formal charge of +2 on the central atom and +1 on the oxygen atom.

We need to construct the resonance structure for CSO

The structure shown in figure

According to question,

A formal charge of +2 on the central atom and +1 on the oxygen atom.

Then tha structure shown in figure

The central atom in the structure is sulphur.

We need to calculate the formal charge on sulphur

Using figure,

charge\ on\ S=+3-1

charge\ on\ S=+2

A formal charge of +2 on the central atom.

This is proved.

Hence, The given condition is proved.

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Need help !!!!! ASAP
Korolek [52]
<h2>Hello!</h2>

The answer is:

The new volume is 2.84 L.

V_{2}=2.84L

<h2>Why?</h2>

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law,  and Boyle's Law.

The law is defined by the following equation:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}

Where,

P_{1} is the first pressure.

V_{1} is the first volume.

T_{1} is the first temperature.

P_{2} is the second pressure.

V_{2} is the second volume.

T_{2} is the second temperature.

So, we are given the following information:

V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K

Then, isolating the new volume, and substituting, we have:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L

Hence, the new volume is 2.84 L.

V_{2}=2.84L

Have a nice day!

4 0
4 years ago
An ideal gaseous reaction (which is a hypothetical gaseous reaction that conforms to the laws governing gas behavior) occurs at
Juli2301 [7.4K]

The total change in internal energy would simply be calculated using the formula:

ΔU = -P (V2 – V1) + ΔH

where ΔU is the change in internal energy; P is constant pressure = 30 atm = 3,039,750 Pa; V2 is final volume = 2 L = 0.002 m^3; V1 is initial volume = 7.20 L = 0.0072 m^3; while ΔH is the heat = -74,400 J (heat released so negative)

 

Therefore:

ΔU =-3,039,750 Pa * (0.002 m^3 - 0.0072 m^3) + (- 74,400 J)

<span>ΔU = - 58,593.3 J = - 58.6 kJ</span>

5 0
4 years ago
Imagine that a single cell below goes through four cell divisions. How many cells are produced? To find out, draw the parent cel
Lisa [10]

16 cells are produced from a single parent cell after the fourth division of the cell.

<h3>What is a cell?</h3>

In biology, the smallest unit can live on its own and that makes up all living organisms and the tissues of the body.

In mitosis type of cell division, one parent cell is divided into two same or different daughter cells. In this way, in the first division, two cells are produced from single parent cells and in the second division, four daughter cells are produced. In the third division, 8 cells are produced from 4 parent cells and in the fourth division, 16 cells are formed from 8 cells.

So we can conclude that 16 cells are produced from a single parent cell after the fourth division of the cell.

Learn more about cell here:

brainly.com/question/13123319

#SPJ1

4 0
2 years ago
A few Sources of error in saponification experiment ?
garri49 [273]

Answer:

Saponification is a process of mixing triglycerides with potassium hydroxide (lye) in order to produce fatty acid and glycerol also known as soap.

During this experiment, many errors can occurs which are following;

  • Incorrect measurement of both the salts that combine to form soap.
  • The beaker and the stirrer has residue of some other chemical that gets mixed with two components and reacts.
  • The two products are not mixed well or not long enough to reach the end product.
  • The temperature is not favorable.
  • The resting period is not calculated properly

I hope the answer is helpful.

5 0
4 years ago
During inhalation, View Available Hint(s) During inhalation, oxygen molecules move into the lungs, and carbon dioxide molecules
bekas [8.4K]

Answer:

the diaphragm and rib muscles contract

Explanation:

Inhalation is the set of movements that allows air to enter the lungs. In this process occurs the contraction of the diaphragm, causing its lowering. The intercostal muscles also contract causing the ribs to lift. This causes the chest to grow larger and the internal pressure of the lungs to become smaller than the external. With the reduction of intrapulmonary pressure, air ends up entering the airways and reaching the alveoli for gas exchange to occur.

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4 years ago
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