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yarga [219]
3 years ago
8

Select the correct answer.

Chemistry
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

option B one inch

Snezhnost [94]3 years ago
7 0

Answer: 2 inches becase I just took the test

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In which aqueous solution will the most ZnS dissolve?
sineoko [7]
1) 0.1 M NaCl
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8 0
3 years ago
Read 2 more answers
It 32g of potassium nitrate can be dissolved in 1cm3 of water at 20oC before a saturated solution is obtained, how much potassiu
Dmitry_Shevchenko [17]

Answer:

160 gm

Explanation:

Five times as much water means you can dissolve 5 times as much potassium nitrate    5 x 32 = 160 gm  <u> <===== this seems unlikely though as I doubt 32 g  of  potassium nitrate will dissolve in only  1 cm^3 of water 1 cm^3 of water is only 1 gm of water </u>

7 0
1 year ago
Al wonders if adding salt to water will affect how long it takes the water to
love history [14]

The hypothesis is that salt water freezes faster than fresh water.

The dependent variable is time taken for ice to appear.

The independent variable is presence or absence of salt

The constants are the amount of water in each tray, freezing conditions and length of time of exposure to freezing condition.

The control group is the tray to which salt was not added

The experimental group is the tray to which salt was added

The presence of solutes in a solution causes the freezing point depression.

A solution is made up of a solute and a solvent. In the presence of a solute, the freezing point of a pure solvent is decreased. This is because freezing point is a colligative property.

Colligative properties depend on the amount of solute present.

Hence, the pure water freezes faster (ice begin to appear earlier) than the salt water.

The hypothesis put forward in this experiment was found to be invalid by the experiment.

For more about colligative properties, see

brainly.com/question/10323760

6 0
2 years ago
For a first-order reaction, A → B, the rate coefficient was found to be 3.4 × 10-4 s-1 at 23 °C. After 5.0 h, the concentration
Illusion [34]

Answer:

the original concentration of A = 0.0817092  M

Explanation:

A reaction is considered to be of first order it it strictly obeys the graphical equation method.

k_1 = \dfrac{2.303}{t}log \dfrac{a}{a-x}

where;

k = the specific rate coefficient  = 3.4 × 10⁻⁴ s⁻¹

t = time   = 5.0 h = 5.0 × 3600 = 18000 seconds

a = initial concentration = ???

a - x = remaining concentration of initial concentration at time t = 0.00018 mol L⁻¹

3.4 \times 10^{-4}= \dfrac{2.303}{18000}log \dfrac{a}{0.00018}

3.4 \times 10^{-4}= 1.27944 \times 10^{-4} \times log \dfrac{a}{0.00018}

\dfrac{3.4 \times 10^{-4}}{1.27944 \times 10^{-4}}=   log \dfrac{a}{0.00018}

2.657=   log \dfrac{a}{0.00018}

10^{2.657}= \dfrac{a}{0.00018}

453.94 = \dfrac{a}{0.00018}

a =453.94 \times 0.00018

a = 0.0817092  M

Thus , the original concentration of A = 0.0817092  M

8 0
3 years ago
What is the formula for copper(ii) phosphate??
Ilia_Sergeevich [38]
It would be Cu3(PO4)2
6 0
2 years ago
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