Select the correct answer.
2 answers:
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Answer: -
2.5
Explanation: -
Initial [HNO₂] = 2.00 M
ka = 5.00 x 10 ⁻⁶
ICE table for HNO₂ =
[
Ka =
5.00 x 10-6 =
x = 0.0032 M
pH = - log [H⁺]
= - log 0.0032
= 2.5
Answer: -
2.5
Explanation: -
Initial [HNO₂] = 2.00 M
ka = 5.00 x 10 ⁻⁶
ICE table for HNO₂ =
[
Ka =
5.00 x 10-6 =
x = 0.0032 M
pH = - log [H⁺]
= - log 0.0032
= 2.5