Moles = n/v where n is the moles of solute and v being the liters of solution.
We can put in the information provided to find the molarity.
Moles = .45/3.0 = .15
So we now know that the molarity of that solution is .15!
I hope I helped you :). Make sure to memorize that formula because it's not that hard as long as you know what to plug in.
Answer:
Molarity is a unit that measures how much moles of solute dissolved in a liter of solvent. Molarity expressed using capital M while molarity, a different unit, expressed using lower case m.
We want to make 0.005 M solution which means we need 0.005 moles of KmnO4 per liter of water. First, we have to calculate how many grams of KMnO4 we need for the solution.
We want to make 250ml solution, so the number of moles of KMnO4 we need will be: 0.005 mol/liter *(250 ml * 1liter/1000ml)= 0.005 mol/liter * 1/4 liter = 0.00125 moles
The molecular mass of KMnO4 is 158g/mol, so the mass of KMnO4 we need will be: 0.00125 moles * 158g/mol= 0.1975 grams
We know that we need 0.1975 g of KMnO4, now we weigh them and put it inside a dish. After that, we prepare Erlenmeyer or a volumetric flask filled with water half of the volume needed(125ml). Pour the weighted solute into the flask, stir until all solute dissolved.
Then we add water to the container slowly until its volume reaches the 250ml mark.
Answer:
V = 48.64 L
Explanation:
Given data:
Mass of CO₂ = 85.63 g
Temperature = 273 K
Pressure = 1 atm
Volume of CO₂ = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 85.63 g / 40 g/mol
Number of moles = 2.14 mol
Volume in Litter:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1 atm× V = 2.14 mol ×0.0821 atm.L/mol.K ×273 K
V = 48.64 atm.L / 1 atm
V = 48.64 L
Answer:
H2 is Molecular hydrogen. It is a molecule of hydrogen that consists of two hydrogen atoms bonded together by one single bond
Explanation:
