The probability that one of each color is selected is
The probability of an event is the chances of the said event
The given parameters are:
The probability that one of each color is selected is calculated as follows:
So, we have:
This gives
Take LCM
Simplify the above expression
Expand
Hence, the probability that one of each color is selected is
Read more about probabilities at:
brainly.com/question/7965468
Answer:
50 is the best choice
Step-by-step explanation:
it is better if its an even number and higher
The HCF of 168 & 196 is 28
The factors of 168 are: 1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168
The factors of 196 are: 1, 2, 4, 7, 14, 28, 49, 98, 196
The highest factor that both 168 and 196 share is 28
Hope this helps :D
If there are 1000 customers in the store one week, how many will purchase exactly one of these items
1000 CUSTOMERS*28%=280
A The event that a persons buys a suit
B The event that a person buys a shirt
C The event that a person buys a tie
P(A)= 22%
P(B)= 30%
P(C)= 28%
P(AB)= 11%
P(AC)= 14%
P(BC)= 10%
P(ABC)= 6%
A u B u C Is the event that any item is bougth
AC u AC u BC Is the event that any two events occured
So the wanted probability is
P[(A u B u C )(AB u AC u BC)^c
P[(A u B u C )=P(AB)+ P(BC)+P(BC)
P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06
=0,51
0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c
=0,28
FCD
Step-by-step explanation: and sometimes we do not care about bold writing
FCD is the vertical angle I guess.
okay.
16/31, 51.612903225807%