8(7+6+11) help please
1 answer:
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Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper = sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining =
=
Using algebraic formula:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
The line that passes through (-2, 1) and (8, 2) is:
y = (1/10)*x + 12/10
<h3>How to find the equation of the line?</h3>I assume you want to find the equation of the line that passes through (-2, 1) and (8, 2).
A general linear equation is written as:
y = a*x + b
If the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope can be written as:
In this case, we know that it passes through (-2, 1) and (8, 2), then:
Then the line is:
y = (1/10)*x + b
To find the value of b, we use one of the given points, for example if we use (8, 2), it means that when x = 8, we must have y = 2.
2 = (1/10)*8 + b
2 - 8/10 = b
20/10 - 8/10 = b
12/10 = b
Then the linear equation is:
y = (1/10)*x + 12/10
If you want to learn more about linear equations:
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