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enot [183]
3 years ago
9

Solve the equation x² + 6x + 1 = 0

Mathematics
2 answers:
dsp733 years ago
8 0

Answer:

x=−3+2√2 or x=−3−2√2

Step-by-step explanation:

Sedaia [141]3 years ago
3 0

Answer:

Two solutions were found :

x =(6-√40)/2=3-√ 10 = -0.162

x =(6+√40)/2=3+√ 10 = 6.162

Step-by-step explanation:

Trying to factor by splitting the middle term

1.1     Factoring  x2-6x-1

The first term is,  x2  its coefficient is  1 .

The middle term is,  -6x  its coefficient is  -6 .

The last term, "the constant", is  -1

Step-1 : Multiply the coefficient of the first term by the constant   1 • -1 = -1

Step-2 : Find two factors of  -1  whose sum equals the coefficient of the middle term, which is   -6 .

     -1    +    1    =    0

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A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of
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The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

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Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

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95% confidence interval

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The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

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The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

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3 years ago
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