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CaHeK987 [17]
4 years ago
15

Equivalent fractions of 3/4?

Mathematics
2 answers:
zhannawk [14.2K]4 years ago
4 0
6/8, 9/12, 12/16, 30/40, 60/80
dimulka [17.4K]4 years ago
4 0
9/12 6/8 18/24


mark me as brainiest please
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gayaneshka [121]
John Paul is correct
7 0
3 years ago
How many square feet of outdoor carpet will we need for this hole?​
yarga [219]

MY WORK:

First, you would cut it up into different parts/shapes

(I cut it up into rectangles)

Then, you would find the area of each.

The bottom rectangle: 10 ( 5 times 2 )

The middle rectangle: 12 ( 6 times 2 )

The top rectangle: 8 ( 4 times 2 )

Lastly, you would add!

10 + 12 + 8 = 30

Therefore, the answer is...

30!

My apologies if this is wrong but I hope I helped a little bit!

7 0
3 years ago
Solve this inequality for x: -46 -8x >22.
olga2289 [7]

Answer:

Step-by-step explanation:

The key to answering this is to know that the only time you'll change the direction of the sign is when you multiply or divide by a negative number.

-46 - 8x > 22

-8x > 22 + 46

-8x > 68

x < 68/-8        (we divided by -8 so the inequality changed direction)

x < -17/2

3 0
3 years ago
Read 2 more answers
Can someone look at these pictures and help me please!? I need to submit this real soon!
vagabundo [1.1K]

Answer:

The answer is 72 minutes

Step-by-step explanation:

Hope this helps :)))

7 0
4 years ago
A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 80% confidence inter
jasenka [17]

Answer:

The 80% confidence interval for the mean

(4.6199 , 4.7801)

Step-by-step explanation:

<u>Explanation</u>:-

Assuming that the population standard deviation for the number of energy drinks consumed each week is 1

Given the Population standard deviation 'σ' = 1

The study found that for a sample of 256 teenagers the mean number of energy drinks consumed per week is 4.7

given sample size 'n' = 256

mean of the sample 'x⁻' = 4.7

<u>confidence interval for the mean</u>

The 80% confidence interval for the mean is determined by

(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\alpha }\frac{S.D}{\sqrt{n} } )

the z-score of 80% level of significance = 1.282

(4.7 - 1.282\frac{1}{\sqrt{256} } , 4.7 + 1.282\frac{1}{\sqrt{256} } )

(4.7 - 0.0801 , 4.7 +0.0801)

(4.6199 , 4.7801)

<u>Conclusion</u>:-

The 80% confidence interval for the mean

(4.6199 , 4.7801)

7 0
4 years ago
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