Answer:
-23x^3+20x^4+25x^2+84x-84
Step-by-step explanation:
1 Expand by distributing sum groups.
4x^2(3x+5x^2-6)-7x(3x+5x^2-6)+14(3x+5x^2-6)
2 Expand by distributing terms.
12x^3+20x^4-24x^2-7x(3x+5x^2-6)+14(3x+5x^2-6)
3 Expand by distributing terms.
12x^3+20x^4-24x^2-(21x^2+35x^3-42x)+14(3x+5x^2-6)
4 Expand by distributing terms.
12x^3+20x^4-24x^2-(21x^2+35x^3-42x)+42x+70x^2-84
5 Remove parentheses.
12x^3+20x^4-24x^2-21x^2-35x^3+42x+42x+70x^2-84
6 Collect like terms.
(12x^3-35x^3)+20x^4+(-24x^2-21x^2+70x^2)+(42x+42x)-84
7 Simplify.
-23x^3+20x^4+25x^2+84x-84
Looking at the problem, what we must do to complete this question is to completely factor the expression that was provided. The expression that was provided is 
.
The first step that we must do is to take a look at the expression and see what the two pieces of the expression have in common. We can see that both 
and 
have the number 5 and the variable c associated with them so we can factor out those two.
<u>Factor out 5c</u>
Now we have completely factored out the expression that was provided in the problem statement and we came to final answer of 
.
Answer:
80 893 720
Step-by-step explanation:
hope dis helps!!!!
A coin has two sides, which means it has a 1/2 chance of landing on each individual side when you flip the coin. Since there is a 1/2 chance of landing on each side, you could expect the coin to land on "Heads' 75 times.
Answer:
35
Step-by-step explanation:
