I don't know 1 but 2 can be 2.3 over 4.5 I think sorry if it's wrong but I hope it helps
Answer: A reflection across the x-axis keeps the x-coordinates the same but flips the signs of the y-coordinates. So, it should be the opposite for a reflection across the y-axis. The y-coordinates remain the same, but the signs of the x-coordinates change.
Step-by-step explanation
I copy and pasted the answer
Answer:
x+1 , x<-1
x²-bx-4 , -1≤x≤4
1/2 x +a
substitute x=-1 , continuous everywhere
x+1=x²-bx-4 when x=-1
-1+1=-1²-b-4
<h2>1+b-4=0 ⇒ +b-3 ⇒ b=3</h2>
then for :
x²-bx-4=1/2 x +a for x=4
4²-4b-4=1/2x+a
16-4(3)-4=4/2+a
16-12-4-2=a
<h2>a=-2</h2>
the equations will be :
x+1
x²-3x-4
1/2x-2
I hope this help
Answer:
or 
Step-by-step explanation:
first use the y2-y1/x2-x1 formula then use y=mx+b after
plug in 2 for y2 and -1 for y1
plug in -5 for x2 and 5 for x1
=
2+1=3
-5-5=-10
is ur slope
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this is the y=mx+b formula *extra info ig*
i usually use the first point for this but u can use watever point u want
plug in 5 for x
plug in -1 for y
and plug -3/10 for m
-1=-3/10(5)+b
-3/10*5=-3/2
-1=-3/2+b
add -3/2 on both sides
-1+3/2=1/2
1/2=b and b is ur y-intercept
y=-3/10x+1/2
hope this helps