If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
ratio of the diagonal to the side of the rectangle is 17/8 or 17:8
Step-by-step explanation:
Length of Diagonal = 34 inches
Length of side = 16 inches
Base= 30 inches
We need to find the ratio of the diagonal to the side of the rectangle.
ratio of the diagonal to the side of the rectangle = 
Putting values:
So, ratio of the diagonal to the side of the rectangle is 17/8 or 17:8
Keywords: ratio
Learn more about ratio at:
#learnwithBrainly
Answer:
multiply 3x-2(x+8)
Step-by-step explanation:
PEMDAS
also you must simplify both sides to solve this problem and that's the first step to simplifying this side (the other one is simplified)
Are you looking for y and if so y=80
X + 60 = 100 (because they are vertical angles, which means that because they are directly opposite of each other, they are of the same measurements).
Solve for x. Isolate the x, subtract 60 from both sides
x + 60 = 100
x + 60 (-60) = 100 (-60)
x = 100 (-60)
x = 40
40° should be your answer
hope this helps
