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3 years ago

Which number is a solution of the inequality m > 13/3a. -9b. 3c. 5d.2

Mathematics

1 answer:

SashulF [63]3 years ago

3 0

m > 13/3

m > 4 1/3

5 is greater than 4 1/3

Answer is c.

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Which point is an x-intercept of the quadratic function

daser333 [38]

The x-intercept of f(x) = (x + 6)(x - 3)
f(x) = 0 → (x + 6)(x - 3) = 0 → x + 6 =0 or x - 3 =0
x = -6 or x = 3
Therefore the x-intercepts are: (-6; 0) and (3; 0)
Your answer is (-6; 0)

8 0

3 years ago

Read 2 more answers

Given the function g(x) = (5 - x)^3 , what is the value of g(2)?

11111nata11111 [884]

Answer:

g(2) = 27 is the answer.

Step-by-step explanation:

If the function is g(x) = (5 - x)³

By expanding (5 - x)³ = 5³-3.5²x + 15x² -x³

g(x) = 125 - 75x + 15x² - x³

Now g(2) = 125 - 75×2 + 15×(2)² - 2³

g(2) = 125 - 150 + 60 - 8

= -25 + 60 - 8

= 35 - 8 = 27

Or directly putting the value x = 2 in g(x) we get

g(2) = (5 - 2)³ = 3³ = 27

Therefore g(2) = 27 is the answer.

3 0

2 years ago

Read 2 more answers

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$