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3 years ago

Which is more 740 yards or 1 mile

Mathematics

2 answers:

Orlov [11]3 years ago

8 0

Answer:

1 mile

Step-by-step explanation:

1 mile is larger because if you put 740 yards in miles it equals 0.42 miles.

So 1 mile is larger than 740 or 0.42 miles

a_sh-v [17]3 years ago

8 0

Answer:

1 mile

Step-by-step explanation:

1 mile is larger because if you put 740 yards in a mile it will equals 0.42 miles. So 1 mile is larger than 740 and 0.42 miles

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Ibought a new shirt at the store for $30. If the tax is 10%, how much is the tax? And how much did I

Vikentia [17]

Answer:

Tax = 3$

Tot Cost = 33$

Step-by-step explanation:

10% of 30$ is 3$

(0.10 * 30 = 3)

the tax is 3$

30$ + 3$ = 33$

the total cost is 33$

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2 years ago

anne buys used cars at auction for 2000 per car. there is 150 fee to take part in the auction. If anne buys 13 used cars how muc

katrin [286]

How to understand the problem is like this:
Total Cost = Entrance Fee + Total Car cost
So we know that the Entrance Fee is $150...
Total Cost = $150 + Total Car cost
So we know that Anne bought 13 cars, each at $2,000...
Total Cost = $150 + ($2,000 x 13)
We multiply because each car is $2,000 and Anne bought 13 of them.
So it works out like this:
Total Cost = $150 + ($2,000 x 13)
Total Cost = $150 + (26000)
Total Cost = $26150

5 0

3 years ago

Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv

Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = $\dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}$

Let dD/dT = 0 to find the critical value we will get

$\dfrac{70000000\left(291T^2-24298T+91800\right)}$ = 0

Using formula of quadratic, we get the roots:

T = 79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

$-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}$