<span>(X^2+6)(4x-3)
</span><span>=<span><span>(<span><span>x2</span>+6</span>)</span><span>(<span><span>4x</span>+<span>−3</span></span>)</span></span></span><span>=<span><span><span><span><span>(<span>x2</span>)</span><span>(<span>4x</span>)</span></span>+<span><span>(<span>x2</span>)</span><span>(<span>−3</span>)</span></span></span>+<span><span>(6)</span><span>(<span>4x</span>)</span></span></span>+<span><span>(6)</span><span>(<span>−3</span><span>)
</span></span></span></span></span>4x3−3x2+24x−18 is the answer
August would be the correct answer.
jus look at the graph, the blue and orange r the closest together in august
Answer: I hope this helps :)
Substitution: 45+15(6-1)
Simplify: 120
Step-by-step explanation:
Calculate within parenthases (6-1) =5 =45+15(5)
Multiply left to right 15(5)=75 =45+75
Add leftg to right 45+75=120
Answer = 120
They're not equivalent.
(vertical bars) represents the absolute value of x. How it works is that it turns negative numbers positive but leaves 0 and positive numbers alone (hence it gets a number's distance from 0 on the number line).
![[x]](https://tex.z-dn.net/?f=%5Bx%5D)
(square brackets) usually represents the floor function, which returns the largest integer that is less than or equal to x. (The floor of x can also be written as 
--- it depends on what your textbook/source says).
To solve 
, you first transform it into the equivalent equation 
. Then by definition of absolute value, there are only two solutions for the first equation: x = 10 or x = -10.
[x] = 10 has infinitely many solutions. For example, the floor of 10 is 10, so ![[10] = 10](https://tex.z-dn.net/?f=%5B10%5D%20%3D%2010)
, thus a solution for the second equation is x = 10
The floor of 10.1 is 10, so ![[10.1] = 10](https://tex.z-dn.net/?f=%5B10.1%5D%20%3D%2010)
, thus another solution for the second equation is x = 10.1.
The two equations do not have the same solution set (as x = 10.1 does not solve |x| - 3 = 7 but solves [x] = 10), so they're not equivalent.
0.90 x 27 = 24.3
you can multiply or put it in a proportion
