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harkovskaia [24]
2 years ago
11

Is it possible that any devices are produced if the production cost is R0. 00​

Mathematics
1 answer:
timama [110]2 years ago
4 0

Answer:

YES,SOMETIMES IT CAN BE PRODUCED

Step-by-step explanation:

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PLEASE HELP<br><br> Write the number in standard form.<br><br> (8 × 10) + (1 × 110) + (6 × 11,000)
mote1985 [20]
66,190 is the Answer if you add 80 to 110 and then add 190 to 66000
7 0
3 years ago
I need the answer for this problem please
Savatey [412]

Answer:

B

Step-by-step explanation:

Find all probabilities:

A. False

Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}

B. True

Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}

C. False

Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}

D. False

Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}

4 0
3 years ago
8. You are planning to use a ceramic tile design in your new bathroom. The tiles are blue-and-white equilateral triangles. You d
ira [324]

Step 1

Find the area of one equilateral triangle

Applying the law of sines

Area=\frac{1}{2} *a*b*sin C

in this problem

a=b=7 cm

C=60 degrees

so

Area=\frac{1}{2} *7*7*sin 60

Area=\frac{1}{2} *49*\frac{\sqrt{3}}{2}  \\ Area=49*\frac{\sqrt{3}}{4}cm²

Step 2

To calculate the area of the hexagon multiply the area of one equilateral triangle by 6

Area Hexagon=6*[49*\frac{\sqrt{3}}{4}]  \\ Area Hexagon=73.5*\sqrt{3}cm²

therefore

the answer is the option

73.5 sqrt 3cm²

3 0
3 years ago
Read 2 more answers
23--2c=41 sorry last question
svlad2 [7]
C=9 np if u need anymore I gotchu
8 0
3 years ago
Read 2 more answers
What are the coordinates of the vertex of the function below write your answer in the form y-9= -6(x-1)^2
Oliga [24]

Answer:

The co-ordinates of the vertex of the function y-9= -6(x-1)^2 is (1, 9)

<u>Solution:</u>

Given, equation is y-9=-6(x-1)^{2}

We have to find the vertex of the given equation.

When we observe the equation, it is a parabolic equation,

We know that, general form of a parabolic equation is  y-9=-6(x-1)^{2}

Where, h and k are x, y co ordinates of the vertex of the parabola.

\text { Now, parabola equation is } y-9=-6(x-1)^{2} \rightarrow y=-6(x-1)^{2}+9

By comparing the above equation with general form of the parabola, we can conclude that,

a = -6, h = 1 and k = 9

Hence, the vertex of the parabola is (1, 9).

7 0
2 years ago
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